Answer:
6.78 × 10⁵ J
Explanation:
Step 1: Given and required data
- Latent heat of vaporization of water (ΔH°vap): 2260 J/g
Step 2: Calculate the heat (Q) required to vaporize 300 grams of water
We will use the following expression.
Q = ΔH°vap × m
Q = 2260 J/g × 300 g
Q = 6.78 × 10⁵ J
6.78 × 10⁵ Joule will be required to convert 300 g of water to steam at 100 °C.
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Answer:
Option B is correct More hydrogen carbonate is formed
Explanation:
Step 1: Data given
The Principle of Le Chatelier says 'If the concentration of one of the reaction partners changes, the balance will shift to counteract that concentration change.
Step 2: When adding more H2O
For the equation CO2 + H2O --> H2CO3
If the H2O concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the right, and so the H2CO3 concentration will increase.
Option B is correct More hydrogen carbonate is formed
