The given alkyne is Option A 3-heptyne
<h3>
What is an Alkyne ?</h3>
The hydrocarbon having at least one C-C triple bond is called an Alkyne.
It has the general formula of 
.
In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.
It has been asked in the question that
CH3CH₂C ≡ CCH₂CH₂CH3 is which alkyne from the given option.
The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .
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Explanation:
Water is a polar solvent as the hydrogen and oxygen atom has large difference in their electronegativities.
Oxygen atom is highly electronegative as compared to hydrogen atom therefore, it pulls the electrons of hydrogen atom closer towards itself.
As a result, two poles will create forming a partial positive charge on the hydrogen atom and partial negative charge on the oxygen atom.
Thus, we can conclude that high electronegativity difference between oxygen and hydrogen is the cause of polarity in water molecules.
<h2>Answer:</h2>
<h2>Explanations</h2>
The complete balanced equation for the given reaction is expressed as;
Given the following parameters
Mass of CH4 = 5.90×10^−3 g = 0.0059grams
Determine the moles of methane
According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:
Determine the mass of water produced
Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams
Answer:
See explanation and image attached
Explanation:
Aromatic compounds undergo electrophilic aromatic substitution reactions in which the aromatic ring is maintained.
Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene depending on the nature of the substituent present in the ring.
Substituents that activate the ring towards electrophilic substitution such as -OCH3 are ortho-para directing.
The major products of the bromination of anisole are p-bromoanisole and o-bromoanisole. The resonance structures leading to these products are shown in the image attached.
Helium
Remember: electron filling of atomic shell ...
The element which have electron in the lowest quantum shell will have the smallest atomic radius\
He:1s1 (Helium)
H:1s2 (hydrogen)
