The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>

Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib

For Addison h=85(1/3)

Subtracting both distances we get

Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
The top answer is the right answer
Hope this helps good luck
Answer:
Step-by-step explanation:
Perimeter of triangle = 4x - 3 + x + 9 + 8
= <u>4x + x</u> -<u> 3 + 9 + 8</u>
= 5x + 14
Area = 

Answer:
take angle U as reference angle
using sine rule
sin U=opposite/hypotenuse
sinU=42/42
sin U=1
sin 90=1
therefore the value of U is 90 degree
Step-by-step explanation:
Multiplier.... multiplier*multiplicand = product