If a molecule can hydrogen bond does it guarantee that it will have a higher boiling point than a molecule that cannot?

1 answer:

6 0

A molecule that can h-bond will not always necessarily and does not have guarantee to have a higher boiling point than one than cannot have h-bond.
we can take an example of Pentan-2-one that cannot h-bond but instead of this it has a high boiling point that is 102.3 °C, while propan-1-ol can h-bond but it has a boiling point of 97.2°C, that is lower than the boiling point of Pentan-2-one.

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A ring costs $36 more than a bracelet. the cost of the bracelet is 4/7 the cost of the ring. find the total of the two items.

avanturin [10]

So let's use some equations to represent the data [let R= cost of ring & B= cost of bracelet]

R= B + $ 36 .... (1)

B= $\frac{4}{7}$ × R ... (2)

By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)

B = $\frac{4}{7}$ × (B + $36)

B = $\frac{4}{7}$ B + $\frac{144}{7}$

$( \frac{7}{7} - \frac{4}{7} ) B = \frac{144}{7}$

$\frac{3}{7} B = \frac{144}{7}$

⇒ B = $48

By substituting value of B into ea (1)

If R = B + $36

R = ($48) + $36

= $84

∴ the total of the two items = R + B
= $84 + $48
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3 years ago

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djverab [1.8K]

Answer:

Answer in explanation

Explanation:

A. This is wrong. The reactants are on the left side of the yields arrow

B. This is wrong. They can only be at one side at a time. They cannot be on both sides at the same time.

C. The products are on the right side of the yields arrow and not at the left side

D. This is correct. The reactants are on the left side of the yields arrow.

E. This is correct. We can have varying numbers of the number of atoms on both side of the yields arrow. The numbers may differ until we decide to balance the equation

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lawyer [7]

Answer:

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Explanation:

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