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Morgarella [4.7K]
4 years ago
8

If a molecule can hydrogen bond does it guarantee that it will have a higher boiling point than a molecule that cannot?

Chemistry
1 answer:
sleet_krkn [62]4 years ago
6 0
A molecule that can h-bond will not always necessarily and does not have guarantee to have a higher boiling point than one than cannot have h-bond.
we can take an example of Pentan-2-one that cannot h-bond but instead of this it  has a high boiling point that is 102.3 °C, while propan-1-ol can h-bond but it has a boiling point of 97.2°C, that is lower than the boiling point of Pentan-2-one.
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If a hydrogen atom has its electron in the n = 3 state, how much energy in ev is needed to ionize it?
tensa zangetsu [6.8K]

The energy of the hydrogen atom will be -0.85 ev.

Ionization, also known as ionization, would be the phenomenon by which an atom or molecule gains or loses electrons to acquire a negative and positive charge, frequently in conjunction with those other chemical changes. Ions are the name for the electrically charged molecular or atom that results.

These chemicals are known as ionic compounds, with table salt serving as an example. Ionization would be the process of removing electrons from such an element as well as a molecule as well as the dissociation of an ionic material, such as salt, itself into the individual ions in a solution like water.

The energy of hydrogen atom will be calculated by using the formula:

E_{n} = -13.6 ev / n^{2}

where, E_{n} = energy of nth level, n is the state.

It is given that, n = 3 .

Now put the value of n in above equation.

E_{4} = -13.6 ev / 4^{2}\\E_{4} = -13.6 ev  / 16\\E_{4} = -0.85 ev

Therefore, the energy of the hydrogen atom will be -0.85 ev.

To know more about energy

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1 year ago
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3 years ago
Identify the balanced equation for the following reaction:<br><br> SO2(g) + O2(g) → SO3(g)
sergiy2304 [10]

Answer:  The balanced equation for the given reaction is

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side.

For example, SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)

Here, number of atoms on reactant side are as follows.

  • S = 1
  • O = 4

Number of atoms on product side are as follows.

  • S = 1
  • O = 3

To balance this equation, multiply SO_{2} by 2 on reactant side and multiply SO_{3} by 2. Hence, the equation will be re-written as follows.

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)

Here, number of atoms on reactant side are as follows.

  • S = 2
  • O = 6

Number of atoms on product side are as follows.

  • S = 2
  • O = 6

Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.

Thus, we can conclude that the balanced equation for the given reaction is 2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

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