Choose an element from the Group that will lose 2 electrons in order to achieve noble gas configuration? What is the group name
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0.017× dissociated H ions are there in 341 ml of an aqueous solution whose ph is 11. 93
If pH = 11.93
pOH = 14.00 - 11.93 = 2.07
[OH- ] =
[OH-] = 0.00851138 M
In 1 L solution we have 0.00851138 M moles OH- ions
In 0.341 L we have,
0.00851138 * 0.341
=0.0029 moles OH- ions
1 mol OH- ions = 6.022*10²³ ions
0.0029 moles OH- ions = ( 0.0029) * (6.022*10²³)
= 0.017×
Therefore, 0.017× dissociated H ions are there in 341 ml of an aqueous solution whose ph is 11. 93
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