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4 years ago

A dog has a leash on that is 4 meters long. What is the total area of the space where the dog can travel?

1 answer:

6 0

There is no limit to the area that the dog can access and explore. It can go anywhere it wants to, and simply drag the leash behind. My dogs do it all the time. Now if you were to fasten the free end if the leash to a stake in the ground, then the situation would be a completely different one. Then the dog would be restricted to the circle centered at the stake with radius=4 meters. The area of such a circle is 16 pi square meters.

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Which properties of equality are used to solve the following (in no particular order)?

guajiro [1.7K]

All except combine like terms. Since you only have 1 variable.

Hope this helps.

r3t40

3 0

3 years ago

The product of two rational numbers is 2/5 , if one of them is -8/25, find the other.

Sergio [31]

Answer:

x=-5/4

Step-by-step explanation:

Let the number be x and y

x.y=2/5 (The product of two rational numbers is 2/5)

if one of the number is -8/25

x.(-8/25)=2/5

(Here Substituted the value of one of the number yoy may substitute the value -8/25 in place of x

x=(2/5) *(-25/8)

x=-5/4

3 0

3 years ago

Read 2 more answers

Line f has a slope of -3. what is the slope of the line that is parallel to line f

andre [41]

Answer:

A line parallel has the same slope, so -3

8 0

3 years ago

Solve each of the following for the indicated variable.a. 9 − 6 = 54 for yb. = 2 + 2 for l

marta [7]

Answer:

$\begin{gathered} y=\frac{9}{6}x-9 \\ l=\frac{P}{2}-w \end{gathered}$

Step-by-step explanation:

To solve the following equations, we need to isolate the variable asked using inverse operations to solve equations.

Remember that addition and subtraction are inverse operations, as multiplication and division.

Therefore,

$\begin{gathered} a\text{. Solve for y} \\ 6y=9x-54 \\ y=\frac{9}{6}x-\frac{54}{6} \\ y=\frac{9}{6}x-9 \end{gathered}$ $\begin{gathered} b\text{. Solve for l} \\ P=2l+2w \\ 2l=P-2w \\ l=\frac{P}{2}-\frac{2}{2}w \\ l=\frac{P}{2}-w \end{gathered}$

4 0

1 year ago

In triangle ABC above, AD is perpendicular to CB. If the lengths of AD and CB were both increased by 50%, how would the area of

astra-53 [7]

Answer:

The answer is below

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene triangle, equilateral triangle, isosceles triangle.

The area of a triangle is given as:

A = (1/2) * b * h

where b = base of triangle, h = height of triangle , A = area

Let BC = base = x, and AD = height = y, hence:

A = (1/2) * x * y = 0.5xy

If the lengths of AD and CB were both increased by 50%, hence:

new AD = y + 0.5y = 1.5y, new CB = x + 0.5x = 1.5x

The new area= (1/2) * 1.5y * 1.5x = 1.125xy

Increased area / area = 1.125xy / 0.5xy = 2.25

If the lengths are increased by 50%, the area would also increase and the new area would be 2.25 times

3 0

3 years ago