Answer:
<em> 508Hz</em>
Explanation:
A tuning fork with a frequency of 512 Hz is used to tune a violin. When played together, beats are heard with a frequency of 4 Hz. The string on the violin is tightened and when played again, the beats have a frequency of 2 Hz. The original frequency of the violin was ______.
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - this phenomenon is beat production
frequency is the number of oscillation a wave makes in one seconds.
f1-f2=beats
therefore f1=512Hz
f2=?
beats=4Hz
512Hz-f2=4Hz
f2=512-4
f2=508Hz
the original frequency of the violin is 508Hz
The gravitational potential energy will increase
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in a gravitational field.
Near the Earth's surface, the GPE of an object is given by

where
m is the mass of the object
g is the acceleration of gravity
h is the heigth of the object above the ground
From the equation, we see that the GPE is directly proportional to the mass: therefore, if the mass increases, the GPE will increase as well.
So, for the beanbag in this problem, when its mass increases, the GPE will increase as well.
Learn more about gravitational potential energy:
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Answer:
The effective (rms) current when the circuit is in resonance is 6 A
Explanation:
Given;
resistance of the resistor, R = 20 ohms
capacitance of the capacitor, C = 0.75 microfarads
inductance of the inductor, L = 0.12 H
effective rms voltage,
= 120
At resonance, the impedance Z = R, Since the capacitive reactance (Xc) is equal to inductive reactance (XL).
The effective (rms) current, =
/ R
= 120 / 20
= 6 A
Therefore, the effective (rms) current when the circuit is in resonance is 6 A
Answer :A testable prediction is also known as a hypothesis.
Explanation: I think
Answer:
Circle Q
Explanation:
The flux of a field through a surface is given by:

where
F is the field strength
A is the area of the surface
is the angle between the direction of the field and the normal to the surface
In the figure, we see that the 4 surfaces have different orientations, so different angle
. In the formula, we see that the flux is maximum when
, which occurs when the field is perpendicular to the surface, and the flux is zero when
, (because
) which occurs when the field is parallel to the surface.
In the figure, we see that circle Q is parallel to the direction of the field, so in this case the field is zero, while in all the other cases is not.
So, the correct answer is
Circle Q