The desk is in equilbrium, so Newton's second law gives
∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0
∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0
==> <em>n</em> = <em>mg</em>
==> <em>p</em> = <em>f</em> = <em>µn</em> = <em>µmg</em> = 0.400 (80.0 kg) <em>g</em> = 313.6 N
The student pushes the desk 3.00 m, so she performs
<em>W</em> = (313.6 N) (3.00 m) = 940.8 Nm ≈ 941 J
of work.
The answer more than likely based on research would be (B.)
Answer:
25N
it will float since the water displaced is less than the weight. buoyancy = 25n down
Explanation:
40 newtons - 25 newtons = 25 newtons
Answer:
30,000N/m²
Explanation:
Given parameters:
Pressure on two legs = 15000N/m²
Total surface area of contact = 0.02m²
Surface area on one leg =
= 0.01m²
Unknown:
Pressure exerted if she stood on one leg = ?
Solution:
Pressure is the force per unit area on a body.
Pressure =
The force she is exerting is due to the weight her both. Standing on both feet and on a single feet is based on the same source of force;
Force = pressure x area
Force = 15000 x 0.02 = 300N
So;
Pressure from one leg =
= 30,000N/m²