Answer:

Explanation:
As we know by energy conservation
All its kinetic energy will convert into thermal energy to raise its temperature

now divide both sides by mass of the object

so change in temperature is given as



Answer:
B
Explanation:
option b stands for less down and cm is less than km
200 MeV of energy
E1/E2=7.61=8
U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.
As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8
In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.
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Explanation:
For the reaction.......
H
2
O
(
l
)
+
Δ
→
H
2
O
(
g
)
WHERE BOTH PRODUCT AND REACTANT ARE AT
100
∘
C
,
..........
Δ
H
∘
vaporization
=
40.66
⋅
k
J
⋅
m
o
l
−
1
And thus we need to assess the molar quantity of the water vaporized......
Δ
H
rxn
=
5.00
⋅
g
18.01
⋅
g
⋅
m
o
l
−
1
×
40.66
⋅
k
J
⋅
m
o
l
−
1
=11.3 kJ