The momentum, p, of any object having mass m and the velocity v is

Let
and
be the masses of the large truck and the car respectively, and
and V_S be the velocities of the large truck and the car respectively.
So, by using equation (i),
the momentum of the large truck 
and the momentum of the small car
.
If the large truck has the same momentum as a small car, then the condition is

The equation (ii) can be rearranged as

So, the first scenario:


So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.
The other scenario:


So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.
12 newtons is your answer
Answer:
54 N
Explanation:
We have two positive charges 12uC and 5 uC ,they are kept at a distance of 10cm.
We have a relation for force between two charges q1,q2 as

Value of k is 
On substituting the values into the equation we get,

Hence the force between them is 54 N.
It is calculated that a)The angular velocity of the wheel is 272.13 rad/s,
b)On the edge of the grinding wheel, the linear speed is 47.62 m/s,
and c) On the edge of the grinding wheel, the acceleration is 12958.08 m/s².
Calculation of angular velocity, linear speed & acceleration:
Provided that,
the diameter of the wheel = 0.35 m
So, the radius, r = 0.35/2 = 0.175 m
As 1 revolution = 2π rad
(a)the angular velocity, ω = 2600 rpm =
rad/s
⇒ω = 272.13 rad/s
So, the angular velocity is 272.13 rad/s.
(b)The linear speed, v = r * ω
⇒v = 0.175 * 272.13
⇒v= 47.62 m/s
(c)The angular acceleration, 
⇒
= 12958.08 m/s²
Learn more about angular velocity here:
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