Answer:
C. the C horizon likely has a rockier texture than the topsoil and subsoil.
Explanation:
because i did it on study island
To be honest with you, there's not enough information here to calculate
the answer, because we don't know the power consumption of the front
porch light. The best we can do is represent that as a variable ... pick a
catchy name for it, which will show up in the final answer, and then you
can 'plug in' (get it ?) whatever size light bulb you want to use over the
front porch.
OK. First we have to give it a name. I could use a single letter, but
that's what everybody else always does. Remember ... this is going to
represent the power (watts) consumed by the front porch light when it's
turned on. It's the symbol that means "Front Porch Light Power" wherever
you see it. I could easily call it x or y or z, but I'm going to call it " FPLP ".
OK. FPLP = power consumption of the light, in watts .
0.001 FPLP = power consumption of the light, in kilowatts (kW).
(1 week) · (7 day/week) · (24 hour/day) = 168 hours .
Energy = (power) · (time) = (0.001 FPLP) · (168 hr) = 0.168 FPLP kWhours
Cost = ($0.17 per kWh) · (number of kWh) = (2.86¢) · (FPLP) .
There it is !
For an example, if you use a 100-W bulb in the front porch light,
then FPLP=100 W. If you leave it on 24/7 for a whole week, then
it's going to cost
(2.86¢) · (FPLP) = (2.86¢) · (100 W) = $2.86
Answer:
10 cos (30)N
Explanation:
So, if we were to visualize it for a sec
we would see 10 as the hypotenuse, 30 as the angle between and would be solving for the adjacent side
So, using basic trig rules,
using the fact that cos(30)=x/10
x=10 cos (30)N
False. The sun from earth looks yellow, orange, or sometimes red, but it is really a big white ball of fire.
Answer:
V = 411.43 V
Explanation:
The two forces as a result of each of the 2 charges are;
F1 = kq1•q/r
F2 = kq2.q/r
Where r = r/2 since we are dealing with potential difference at a point midway between the charges.
q1 = 5 nC = 5 × 10^(-9) C
q2 = 3 nC = 3 × 10^(-9) C
k = 9 × 10^(9) N.m²/C²
r = 35 cm = 0.35m
r/2 = 0.35/2
Thus;
F1 = (9 × 10^(9) × 5 × 10^(-9) × q)/(0.35/2)²
F1 = 1469.39q
F2 = (9 × 10^(9) × 3 × 10^(-9) × q)/(0.35/2)²
F2 = 881.63q
Net force acting midway is;
F_net = F1 + F2
F_net = 1469.39q + 881.63q
F_net = 2351.02q
Now, we know that formula for electric potential is;
V = kq/r
Thus ;
V = Fr/q derived from the earlier equation for force we used.
Where F is F_net.
V = 2351.02q × r/q
V = 2351.02r
Recall that we are dealing with midpoint and r = r/2
Thus;
V = 2351.02 × 0.35/2
V = 411.43 V