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KatRina [158]
3 years ago
14

At which angle must a charged particle be moving to experience the greatest magnetic force?

Physics
2 answers:
Anastasy [175]3 years ago
7 0
B) 90° Hope this helps
Natali5045456 [20]3 years ago
6 0

Answer: The correct answer is "90 to the magnetic field".

Explanation:

The expression for Lorentz force is as follows;

F=qE+qvBsin\theta

Here, q is the charge, E is the electric field, B is the magnetic field, v is the velocity, B is the magnetic field and \theta is the angle between the speed of the particle and the magnetic field.

If the speed of the charged particle is perpendicular to the magnetic field, in this case, there is maximum magnetic force.

Put \theta= 90 in the above expression.

F=qE+qvBsin90

F=qE+qvB

Therefore, at 90 to the magnetic field, a charged particle must be moving to experience the greatest magnetic force. The correct option is (B).

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Explain two scenarios where a large truck can have the same momentum as a small car.
KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

p=mv\cdots(i)

Let M_L and M_S be the masses of the large truck and the car respectively, and V_L and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck = M_LV_L

and the momentum of the small car = M_SV_S.

If the large truck has the same momentum as a small car, then the condition is

M_LV_L=M_SV_S\cdots(ii)

The equation (ii) can be rearranged as

\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}

So, the first scenario:

\frac {M_L}{M_S}=\frac {V_S}{V_L}

\Rhghtarrow M_L:M_S=V_S:V_L

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\frac{M_L}{V_S}=\frac{M_S}{V_L}

\Rhghtarrow M_L:V_S= M_S:V_L

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0
3 years ago
Polly is pushing a box across the floor with a force of 30 n. the force of gravity is –8 n, and the normal force is 8 n. which v
Rudiy27
It's -30N is the correct answer
3 0
3 years ago
Read 2 more answers
What is the force of a 3kg ball that is accelerating at 4 m/s/s
Dafna11 [192]
12 newtons is your answer
8 0
3 years ago
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Two positive point charges of 12uc and Suc
GarryVolchara [31]

Answer:

54 N

Explanation:

We have two positive charges 12uC and 5 uC ,they are kept at a distance of 10cm.

We have a relation for force between two charges q1,q2 as

F=\frac{kq1q2}{r^{2} }

Value of k is 9*10^9

On substituting the values into the equation we get,

F=\frac{9*10^9*12*5}{10^9*10}\\\\  F=54N

Hence the force between them is 54 N.

7 0
3 years ago
A grinding wheel 0.35 m in diameter rotates at 2600 rpm .
ddd [48]

It is calculated that a)The angular velocity of the wheel is 272.13 rad/s,

b)On the edge of the grinding wheel, the linear speed is 47.62 m/s,

and c) On the edge of the grinding wheel, the acceleration is 12958.08 m/s².

Calculation of angular velocity, linear speed & acceleration:

Provided that,

the diameter of the wheel = 0.35 m

So, the radius, r = 0.35/2 = 0.175 m

As 1 revolution = 2π rad

(a)the angular velocity, ω = 2600 rpm = \frac{2600 * 2\pi }{60} rad/s

⇒ω = 272.13 rad/s

So, the angular velocity is 272.13 rad/s.

(b)The linear speed, v = r * ω

⇒v = 0.175 * 272.13

⇒v= 47.62 m/s

(c)The angular acceleration, a=\frac{v^{2} }{r}

a = \frac{(47.62)^{2} }{0.175}

⇒a = 12958.08 m/s²

Learn more about angular velocity here:

brainly.com/question/13649539

#SPJ1

6 0
2 years ago
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