3(1+2)
3+6
9 ( the answer is nine)
first you divide six and two then use the distributive property to multiply three and one and three and two, then add three and six to get nine.
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Two squares root. Because 3 * 3 = 9 and -3 * -3 = 9.
Answer:
y=11
Step-by-step explanation:
Solve the system by substitution by setting the equations equal to each other.
y = 5x+6
y = x+10
It becomes 5x+6 = x+10. Solve for x using inverse operations.
5x+6 = x+10
4x+6 = 10
4x = 4
x=1
Substitute x=1 into one equation to find y.
y = x+10
y = 1 +10
y=11
