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2 years ago

Explain why the open umbrella hit the ground after the closed umbrella. *

Physics

1 answer:

balandron [24]2 years ago

7 0

Answer:

An open umbrella would not hit the ground in front of the closed one.

Explanation:

The closed umbrella would impact first because it did not have as much air pressure. The open one has air that presses against it and makes it reach where the open umbrella floats but falls slowly

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Two protons are 1 × 10−10 m apart (about one atomic radius). Which interaction between two protons is stronger, the gravitationa

anastassius [24]

Answer: The electric repulsion between the two protons is stronger than the gravitational attraction.

Explanation: Please see the attachments below

4 0

3 years ago

Which of the following processes DOES NOT occur during the convective transfer of heat within a container of air? Group of answe

vovangra [49]

The volume of a warmed part of the air is reduced and its density increases.

Explanation:

In a convective form of heat transfer, the volume of a warmed part of air is not reduced and its density does not increase.

During convection, heat causes the warm part of the air to expand and its volume increases. When volume increases, density is reduced.

Convection is a form of heat transfer that involves the actual movement of particles of the medium.
It usually occurs in fluids i.e gases and liquids.
In convection, the cold part exerts a buoyant force on the warmer air below and causes it to rise.
As the warmer part is rising the cooler part replaces it and a convective cell is formed in the process.

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Energy transfer in the sun brainly.com/question/1140127

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7 0

3 years ago

Consider two sizes of disk, both of mass M. One size of disk has radius R; the other has radius 4R. System A consists of two of

Harman [31]

Answer:

4 smaller disks

Explanation:

We are given;

Mass of smaller and larger disks = M

Radius of smaller disk = R

Radius of larger disk = 4R

Formula for moment of inertia about cylinder axis is:

I = ½MR²

Thus;

For small disk, I_small = ½MR²

For large disk, I_large = ½M(2R)² = 2MR²

We are told that moment of inertia of System A consists of two of the larger disks. Thus;

I_A = 2 × I_large = 2 × 2MR²

I_A = 4MR²

We are also told that System B consists of one of the larger disks and a number of the smaller disks. Thus;

I_B = I_large + n(I_small)

Where n is the number of smaller disks.

I_B = 2MR² + n(½MR²)

I_B = MR²(2 + n/2)

We are told that the moment of inertia for system A equals the moment of inertia for system B. Thus;

I_A = I_B

So;

4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

5 0

2 years ago

The angular velocity (in rpm) of the blade of a blender is given in. If θ=0rad at t=0s, what is the blade's angular position at

Liula [17]

Answer:

θ = 20.9 rad

Explanation:

In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship

w = θ / t

θ = w t

if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians

suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system

w = 10 rpm $(\frac{2\pi rad}{1 rev}) ( \frac{1 min}{60 s} )$

= 1,047 rads

let's calculate

θ = 1,047 20

θ = 20.9 rad

7 0

3 years ago

A solid sphere rolls without slipping down an incline, starting from rest. At the same time, a box starts from rest at the same

NISA [10]

Answer:

The box arrives first.

Explanation:

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4 0

2 years ago