Question

A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s

Answer 1

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = $\frac{m}{m+M}$

calculemos

            v= $\frac{0.200}{0.200+M} 0.450$

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂