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xxTIMURxx [149]
3 years ago
12

Solve X³=64. im trying to finsh my class ​

Mathematics
2 answers:
bagirrra123 [75]3 years ago
6 0

Answer:

C

Step-by-step explanation:

multiply the number 3 times

A    1536

B     512

<h2>C 64!!!</h2>

D Dum answer choice

Scrat [10]3 years ago
4 0

Answer:

x = 4

Step-by-step explanation:

We have the equation x^3 = 64 and are asked to solve for x.

To solve, we need to isolate x.

x^3 = 64

Cube root both sides by 3 to get x alone :

(x^3)^3 = \sqrt[3]{64}

x = \sqrt[3]{64}

Solve for the cube root of 64 :

\sqrt[3]{64} = 4

x = 4

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Can you please solve this!!
lyudmila [28]

Answer: A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve 5(5x + 3) = -10​
Elena-2011 [213]

Answer: it is -1

Step-by-step explanation:

5*5x=25x

5*3=15

25x+15=-10

25x= -10-15

25x= -25

X=-25/25

= -1

7 0
3 years ago
Find the values of x and y!!
riadik2000 [5.3K]

Answer:

1st option

Step-by-step explanation:

7x + 7 and 112 are vertically opposite angles and are congruent , then

7x + 7 = 112 ( subtract 7 from both sides )

7x = 105 ( divide both sides by 7 )

x = 15

4y and 112 are adjacent angles and sum to 180° , that is

4y + 112 = 180 ( subtract 112 from both sides )

4y = 68 ( divide both sides by 4 )

y = 17

3 0
2 years ago
AB = 2x – 17, AC = 14, and BC = x + 1.<br> Find x.
Volgvan

9514 1404 393

Answer:

  • x = 10
  • AB = 3
  • BC = 11

Step-by-step explanation:

If B lies between A and C on a line segment, then ...

  AB +BC = AC

  (2x -17) +(x +1) = 14

  3x = 30 . . . . . . . . . . . . . add 16, collect terms

  x = 10 . . . . . . . . . . . divide by 3

  AB = 2(10)-17 = 3

 BC = 10+1 = 11

3 0
3 years ago
Simultaneous linear equations
Talja [164]
<span>1) 3x + y = 23
6x + y = 44

Subtract 1st from 2nd, 
3x = 21
x = 7
Then, y = 23 - 3(7) = 2

In short, Your Answer would be: (7, 2)

2) </span><span>4x - 3y = 21
2x + 3y = 33

Add the equations, 
6x = 54
x = 9
Then, 2(9) + 3y = 33
3y = 33 - 18
y = 15/3
y = 5

In short, Your Answer would be: (9, 5)

3) </span><span>5x + 2y = 13
6y + 5x = 29
Subtract 1st from 2nd equation, 

4y = 16
y = 4
Then, 5x  = 13 - 2(4)
x = 5/5 = 1

In short, Your Answer would be: (1, 4)

4)  </span><span>5x - 4y = 2
10x - 4y = 32
Subtract 1st from 2nd equation, 
5x = 30
x = 6

Then, 5(6) - 2 = 4y
y = 28/4 = 7

In short, Your Answer would be: (6, 7)

5) </span><span>2x + 7y = 48
x + 3y = 21

Here, x = 21-3y
Substitute in in 1st equation, 
2(21-3y) + 7y = 48
42 - 6y + 7y = 48
y = 6

Then, x = 21 - 3(6) = 3

In short, Your Answer would be: (3, 6)

6) </span><span>8x - 3y = 44
2y - 4x = -20

Multiply 2nd equation by 2 
-8x + 4y = -40
Now, add it to 1st equation, 
y = 4

Then, 2(4) - 4x = -20
4x = 8 + 20
x = 28/4 = 7

In short, Your Answer would be: (7, 4)

Hope this helps!</span>
8 0
3 years ago
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