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Agata [3.3K]
3 years ago
8

What is (3×10) ×8= ------ × (10×8) elementary 5th grade

Mathematics
2 answers:
ipn [44]3 years ago
8 0
Using the property (a\times b) \times c = a \times (b\times c), we know that 3 is the missing number.
Tamiku [17]3 years ago
4 0
This is an example of the commutative property of multiplication.

That property states: (a \times b) \times c = a \times (b \times c)

So using that property, we can figure out that 3 should be in the blank.
You might be interested in
The solution to 2x - 2 + 5 = 13 is
san4es73 [151]
2x - 2 + 5 = 13 

<span>2x = 13 + 2 - 5 or 10 </span>

<span>x = 5</span>
4 0
3 years ago
What is the solution of the following system of equations? -2x+y-z=-8 2x+2y-z=-3 x-y+2x=7
ivolga24 [154]

Answer:

there is so much going on I can't even answer the question lol.

5 0
3 years ago
How do I work this out???
Finger [1]
Okay so form a right angle triangle and the angle of that is 65 as it is right angle so 90 - 25= 65. label the sides like the pic below. 

we have the hypothenuse as well as the angle and we are trying to find the o(opposite side) 

o/h =sin
sin 65=23/h
sin 65 = 23/x
23/sin 65=x 
x=25.4
how high the kite is above ground is :
= 25.4 +1.2
 =26.6

7 0
3 years ago
What is the oblique asymptote of the function f(x) = the quantity x squared minus 5x plus 6 over the quantity x minus 4?
Paraphin [41]

Answer:

x - 1

Step-by-step explanation:

We know that, a slant or oblique asymptote of a rational function is the asymptote that helps in determining the direction of the function.

It occurs when the polynomial in the numerator is a higher degree than the polynomial in the denominator.

Now, we divide the numerator by denominator using long division method and the first two terms in the quotient ( forming a linear function ) is the equation of the oblique asymptote.

We are given the rational function, f(x) = \frac{x^{2}-5x+6}{x-4}.

After dividing we get that, the quotient is x - 1.

Hence, the equation of the oblique asymptote is x-1.

4 0
4 years ago
Plot the corresponding points for the inverse of the function represented by this table of values. x -4 0 3 7
NNADVOKAT [17]

Answer:

See explanation

Step-by-step explanation:

Given the function f(x) for which

\begin{array}{ccccc}x&-4&0&3&7\\ \\f(x)&9&5&2&-2\end {array}

If you want to plot the corresponding points for the inverse of the function f(x), change f(x) into y:  

\begin{array}{ccccc}x&-4&0&3&7\\ \\y&9&5&2&-2\end {array}

switch x and y

\begin{array}{ccccc}y&-4&0&3&7\\ \\x&9&5&2&-2\end {array}

and then change y into f^{-1}(x).

You get

\begin{array}{ccccc}x&9&5&2&-2\\ \\f^{-1}(x)&-4&0&3&7\end {array}

Now plot these points on the coordinate plane (see attached diagram).

3 0
3 years ago
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