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ankoles [38]
3 years ago
13

A 5.18-g sample of a mixture of MgBr2(s) and sucrose (C12H22O11) is dissolved in water and all the bromide is precipitated as Ag

Br(s). If the AgBr(s) precipitate has a mass of 7.65 g, what is the mass percent of MgBr2(s) in the mixture?
Chemistry
1 answer:
vazorg [7]3 years ago
6 0

Answer: 62.8%

Explanation:

step 1: Calculate the number of moles (n) for AgBr.

n(AgBr) = mass(AgBr) / Molar mass(AgBr)

             = (7.65g) / (187.77g/mol)

             = 0.0407 mol

step 2: Determine the number of moles of Br in AgBr.

1 mol AgBr = 1 mol of Br

therefore; n(Br) = 0.0407mol

step 3: Calculate the mass of Br precipitated.

m(Br) = n(Br) × Molar mass(Br)

          = (0.0407 mol) / (79.904g/mol)

          = 3.255g

step 4: Calculate the mass percent of MgBr₂.

%MgBr₂ = mass(Br) / mass(MgBr₂ + C₁₂H₂₂O₁₁) × 100

              = (3.225g / 5.18g) × 100

              = 62.8%

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An aqueous solution of __________ will produce a basic solution. nacl nh4clo4 na2so3 kbr nahso4
scoundrel [369]
I think the correct answer would be NH4ClO4. It would produce a basic solution since as it dissociates into ions OH ions are being formed as the concentration of this increases, the pH of the solution would increase as well making it basic. Hope this helps.
5 0
3 years ago
Calculate the gravitational force of attraction between a 26kg boy and his 5.1kg dog when they are separated by 0.19m
Pavel [41]

Answer:

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

Explanation:

Given:

Mass M1 = 26 kg

Mass M2 = 5.1 kg

Distance r = 0.19 m

Find:

Gravitational force of attraction G(f)

Computation:

Gravitational force of attraction G(f) = G(m1)(m2)/r²

Gravitational force of attraction G(f) = [6.67 x 10⁻¹¹](26)(5.1)/(0.19)²

Gravitational force of attraction G(f) = 8.84 x 10⁻⁹ / 0.0361

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

6 0
3 years ago
Show your calculation by uploading a picture. Calculate the molar mass of ammonia, NH3
Cloud [144]

Answer:

17.04 g/mol

Explanation:

Molar Mass of NH₃

we know that

Nitrogen has 14.01 gram/mol

And Hydrogen has 1.01 gram/mol

but we have 3 Hydrogens So we multiply

1.01 by 3 i.e., 3.03

Now, add

14.01

+<u> </u><u>3</u><u>.</u><u>0</u><u>3</u>

17.04

So, The molar mass of ammonia, NH₃ is

17.04 g/mol

<u>-TheUnknown</u><u>Scientist</u>

5 0
3 years ago
PLEASE HELP ME YOU DONT HAVE TO DO WORK JUST TELL ME IF ITS RIGHT ON THE ORGANIC AND INORGANIC SIDE PLEASEE
Fittoniya [83]

Answer:

Its right you dont have to change anything

3 0
3 years ago
The sp of pbbr2 is 6. 60×10−6. what is the molar solubility of pbbr2 in pure water?
Inessa05 [86]

Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.

Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.

Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.

Let the molar solubility be S upon dissociation.

PbBr₂ or Lead Bromide dissociates in pure water as follows:

                          PbBr₂ ----------> Pb⁺² + Br⁻

                                                     S      2S

Ksp = [Pb⁺²] [ Br⁻]

Ksp = (S) (2S)²

Ksp = 4S³

6.60 × 10⁻⁶ = 4S³

S = 0.0118M

Hence, the Molar solubility S is 0.0118M.

Learn more about Molar solubility here, brainly.com/question/16243859

#SPJ4

6 0
2 years ago
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