Assume 1 liter = 1 kilogram of water = 1000 grams of water.
Part A)
MW of hydrogen is 1.008g/mol, and oxygen is 16.00g/mol.
Find the MW of water by
2*(1.008) + (16.00) = 18.016g/mol.
Convert 1000g H2O to moles :
(1000g H2O)*(1mol H2O / 18.016g H2O) = 55.51 mol
Part B)
Using the answer from part A and Avogadro's number:
(55.51mol)*(6.022*10^23) =
3.343*10^25 molecules.
Hope this is helpful
To estimate the molar mass of the gas, we use Graham's law of effusion. This relates the rates of effusion of gases with their molar mass. We calculate as follows:
r1/r2 = √(m2/m1)
where r1 would be the effusion rate of the gas and r2 is for CO2, M1 is the molar mass of the gas and M2 would be the molar mass of CO2 (44.01 g/mol)
r1 = 1.6r2
1.6 = √(44.01 / m1)
m1 = 17.19 g/mol
Answer: Fluorine contains seven valence electrons. It needs one more electron to complete its octet. The oxidation number is 1- and indicates fluorine will gain or share one electron when it combines with another atom to become a more stable compound.
Explanation: Fluorine contains seven valence electrons. It needs one more electron to complete its octet. The oxidation number is 1- and indicates fluorine will gain or share one electron when it combines with another atom to become a more stable compound.
The molar mass of Ca(ClO4)2 is 239.1 g/mol.
