The biggest thing you're doing wrong is ignoring the units
when you're working with the quantities.
Now let's look at the rest of the problem:
The formula you used is correct:
Net flux through the surface = (net charge inside) / ε₀
and ε₀ = 8.85 x 10⁻¹² farad/meter.
What's the net charge inside the surface in this problem ?
It's (5.85 x 10⁷ electrons) x (the charge on each electron)
= (5.85 x 10⁷ electrons) x (-1.6 x 10⁻¹⁹ coulomb/electron)
= -9.36 x 10⁻¹² coulomb .
Finally, (net charge inside) / ε₀
= (-9.36 x 10⁻¹² coulomb) / (8.85 x 10⁻¹² farad/meter)
= -1.058 newton-m²/coulomb .
The sign and the significant figures in your answer are correct, so
we can see that you know what you're doing. The only thing left is
the order of magnitude. You most likely took one of the negative
exponents and made it positive. You got an answer that's 10²² too
small. Big deal. You could claim "that's close", and see whether you
can convince a teacher.
A vibrating stretched string has nodes or fixed points at each end. The string will vibrate in its fundamental frequency with just one anti node in the middle - this gives half a wave.
Rearranging for the wavelength
Therefore the longest wavelength standing wave that it can support is 14m
In covalent bonds the atoms share electrons.
C. diffraction
Diffraction by description is occurrence
where the sound wave is interrupted or interacts with certain obstructions or
barriers. According to Huygens-Fresnel principle, it is where the waves are interfered
by said circumstances during its travel in the confined specific space.
Furthermore, the amount of
size the wavelength is directly proportional to its interacted slit or barrier
thus, these behaviors and amount are positively correlated.
Moreover, it occurs in a variety
of waves –may it be sound waves, water waves or electromagnetic waves.
Answer:
frequency of the hum = 81 Hz
Explanation:
The velocity of the wave is determined by the relation
v = √(T/miu)
where v = velocity of the wave
T = tension on the string
miu = mass per unit length of the string or linear density = m/L
but here m= 5g = 0.005kg
L = 0.9 m
miu = 0.005/0.9 = 0.00556kg/m
To get the tension on the string we multiply the mass of the sculpture by the acceleration due to gravity, 9.8m/s²
T = 12kg x 9.8m/s² = 117.6 N
hence,
v= √(117.6/0.00556)
v = 145.43 m/s
But
wavelength = 2L = 2 x 0.9 = 1.8m
Also,
frequency = velocity/ wavelength
f = 145.43/1.8 = 80.7967 Hz
The frequency of the hum is 80.8Hz approximately 81Hz