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4 years ago

A tree is 257 ft high. To the nearest tenth of a meter, how tall is it in meters? There are 3.28 ft in 1 m.

Physics

1 answer:

olga2289 [7]4 years ago

7 0

Answer:

Height of tree = 78.35 meters.

Explanation:

We have

1 meter = 3.28 feet

That is

$1 ft = \frac{1}{3.28}=0.3048m$

Here height of tree = 257 ft

Height of tree = 257 x 0.3048 = 78.35 m

Height of tree = 78.35 meters.

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(a) The initial speed at which the bottles are launched is 4.27 m/s.

(b) The horizontal displacement at which the bottle land is 1.75 m.

<h3>Initial speed of the bottle</h3>

The initial speed of the bottle is calculated as follows;

$T = \frac{2usin\theta}{g}$

where;

T is time of flight
u is the initial speed

2usinθ = Tg

u = Tg/(2sinθ)

u = (0.5 x 9.8)/(2 x sin35)

u = 4.27 m/s

<h3>Horizontal displacement of the bottle</h3>

X = u²sin(2θ)/g

X = (4.27² x sin(70))/(9.8)

X = 1.75 m

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Which of the following materials is necessary to stop an alpha particle? a. three feet of concrete c. single sheet of aluminum f

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A single sheet of paper can stop an alpha particle

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4 years ago

Read 2 more answers

I would like to know why this is the correct answer

Helen [10]

The acceleration of the object if the net force is decreased = 0.13 m/s²

<h3>Further explanation</h3>

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

$\tt \sum F=m.a$

The mass used in state 1 and 2 remains the same, at 1.5 kg

state 1

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

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state 2

ΣF=0.2 N

m=1.5 kg

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