Answer:
E = 169.34 J
Explanation:
First, we need to find the frictional force between the back tire and the road. For that purpose, we use the following formula:
f = μR = μW
f = μmg
where,
f = frictional force = ?
μ = coefficient of friction between tire and road = 0.8
g = 9.8 m/s²
m = mass supported by back tire = (0.5)(90 kg) = 45 kg
Therefore,
f = (0.8)(45 kg)(9.8 m/s²)
f = 352.8 N
Now, for the heat energy we use the formula of work. Because, thermal energy will be equal to work done by frictional force:
E = W = fd
where,
E = Thermal Energy = ?
f = frictional force = 352.8 N
d = displacement = 48 cm = 0.48 m
Therefore,
E = (352.8 N)(0.48 m)
<u>E = 169.34 J</u>
Work is force times
distance. <span>
The distance is 1.3 m/s x 7.6 s = 9.88 m </span>
<span>
the force is only sufficient force to overcome friction.
Assuming the table is a level table, the force to overcome friction is µ x
normal force = 0.6 x (12 kg) x 9.8 m/s^2 = 70.56 N </span>
<span>
So the work is 70.56 N x 9.88 m = 697.13 J
<span>The power is simply the work / time = 697.13 J / 7.6 s = 91.7
or 92 Watts </span></span>
Answer:
1.5 m/s^2
Explanation:
Force = 3000 Newtons
Mass = 2000 kilograms
Force = Mass x Acceleration
This rearranged to:
Acceleration = Force / Mass
Acceleration = 3000 / 2000 = 1.5 m/s^2
Answer:
-14.2m/s
Explanation:
Given parameters:
Initial velocity of the ball = 25m/s
Time = 4s
Unknown:
Final velocity of the ball = ?
Solution:
To solve this problem, we use the expression below;
v = u - gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 25 - (9.8 x 4) = -14.2m/s
Answer:
Explanation:
mass of the proton is given is
also we know that charge of proton is same as charge of electron
now we need to find the charge mass ration of proton
so here we have
So above is the charge mass ratio of proton