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mr_godi [17]
2 years ago
15

You have just weighed the same beaker twice, obtaining the following measurements. 50.12 g and 50.25 g. The accepted value of th

e beaker is 47.52 g. Calculate the percent error of the 50.129 beaker.​
Chemistry
1 answer:
ludmilkaskok [199]2 years ago
8 0
50.129-47.52= 2.609
2.609/100%= 2.609
I’m not sure if I did this right.
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a technician mixes 80 ml of a 5% solution with 10 ml of water. what is the final percentage strength of the solution prepared?
Vinvika [58]

A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

given that :

8 ml of a 5 % solution mix with 10 ml . that means the 80 mL of 5 % solution is diluted with water of 10 mL

therefore, 80 × 5 = 10 × x %

x % = 40 %

Therefore, the final percentage strength of the solution is 40 %

Thus, A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

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Convert 1.7 Kg to cg
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To answer this lets first see how much 1 kg is equal to in cg.

1 kg = 100000 cg 

Now lets multiply:-

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So, 1.7 kg = <span>170000 cg
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Answer:

The orbital notations shows the sequence of filling electrons into the orbitals of sublevels. This filling is based on some certain principles. For an atom with 16 electrons, the orbital diagram is shown below:  1s²2s²2p⁶3s²3p⁴ The maximum number of electrons in each sublevel of the orbitals are: 2 electrons for s-sublevel with one orbital

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Explanation:

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