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Naya [18.7K]
3 years ago
12

When a piece of solid phosphorus is added to a flask containing chlorine gas, heat is evolved?

Chemistry
1 answer:
Sav [38]3 years ago
7 0
White phosphorus burns spontaneously in chlorine to produce a mixture of two chlorides, phosphorus (ii) chloride and phosphorus(v) chloride and heat is evolved. Phosphorus (iii) chloride is a colorless fuming liquid: 
P4 + 6Cl2 = 4PCl3
Phosphorus (v) chloride is an off-white solid
P4 +10Cl2 = 4PCl5

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Type your response in the box.
Wittaler [7]

Answer:

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Explanation:

This is the actucal answer so you might want to change it up

8 0
3 years ago
A. Identify which sets of quantum numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).
Butoxors [25]

Answer:

a. Values are - (1) 3,1,-1,1/2        (2) 2,1,-1,-1/2       (3) 3,0,0,1/2    (4) 4,3,3,-1/2

(5) 3,2,2,1/2

b. Order be- I > Sn > Xe

Explanation:

a.

Valid quantum numbers are -

'l' value should be less than 'n' value and 'ml' value should be '-l' to 'l'

'ml' value should not more than 'l' or 'n'.

Values are -

3,1,-1,1/2

2,1,-1,-1/2

3,0,0,1/2

4,3,3,-1/2

3,2,2,1/2

b.

Given that-

I [Kr]4d¹⁰5s²5p⁵

Sn [Kr]4d¹⁰5s²5p²

Xe [Kr]4d¹⁰5s²5p⁶

Order be-

I > Sn > Xe

Xe is least because it is completely filled outer shell (5s²5p⁶

4 0
3 years ago
Consider the Gibbs energies at 25 ∘C.
zysi [14]

Answer:

A)Δ​G​r​x​n​∘​=​55.7​k​J​/​m​o​l

B)Ksp=1.75×10^−10

C)Δ​G​r​x​n​∘​=​70.0​k​J​/​m​o​l

D)Ksp=5.45×10^−13

Explanation:

ΔGrxn∘=​Δ​G​f​,​p​r​o​d​u​c​t​s​∘​−​Δ​G​f​,​r​e​a​c​t​a​n​t​s​∘

To calculate for the

Ksp

of the dissolution reaction can be claculated

ΔGrxn∘=−RTlnKsp

where R is the proportionality constant equal to 8.3145 J/molK.

A)

Δ​G​r​x​n​∘​=​[​Δ​G​f​,​A​g​(​a​q​)​+​∘​+​Δ​G​f​,​C​l​(​a​q​)​−​∘​]​−​Δ​G​f​,

A​g​C​l​(​s​)​⇌​A​g​(​a​q​)​+​+​C​l​(​a​q​)​−

ΔG∘rxn=[77.1kJ/mol+(−131.2kJ/mol)]−(−109.8kJ/mol)

Δ​G​r​x​n​∘​=​55.7​k​J​/​m​o​l

b) Calculate the solubility-product constant of AgCI.

ΔGrxn∘=−RTlnKsp

55.7​k​J​/​m​o​l​=​−​(​8.3145​×​10​−​3​J​/​m​o​l​K​)​(​298.15​K)InKsp

Ksp=1.75×10^−10

c) Calculate

To calculate ΔG°rxn

for the dissolution of AgBr(s).

Δ​G​r​x​n​∘​=​[​Δ​G​f​,​A​g​(​a​q​)​+​∘​+​Δ​G​f​,​B​r​(​a​q​)​−​∘​]​−​Δ​G​f​,

Δ​G​r​x​n​∘​=​[​77.1​k​J​/​m​o​l​+​(​−​104.0​k​J​/​m​o​l​)​]​−​(​−96.90kj/mol

Δ​G​r​x​n​∘​=​70.0​k​J​/​m​o​l

d)To Calculate the solubility-product constant of AgBr.

ΔGrxn∘=−RTlnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K)lnKsp

70.0​k​J​/​m​o​l​=​−​(​8.3145​×​10​−​3​J​/​m​o​l​K​)​(​298.15​K

Ksp=5.45×10^−13

8 0
3 years ago
What does it mean if the plus sign is positive for the sodium atom?
solniwko [45]

The charge of the ion is +1

5 0
3 years ago
Ag + HCl --&gt; ?<br> a) No reaction<br> b) AgCl + H2<br> c) AgCl + H2O<br> PLEASE HELP
Volgvan

Answer:

AgCl + H2 - Chemical Equation Balancer.

8 0
3 years ago
Read 2 more answers
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