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dolphi86 [110]
3 years ago
12

2C(s) + 2H2(g) + 52.4kJ ⇋ C2H4(g)

Chemistry
1 answer:
PtichkaEL [24]3 years ago
3 0

Answer:

A. The equilibrium will shift towards the right, towards the formation of products

B. The concentration of hydrogen gas will decrease as more of it is used in the formation of products

C. Increasing the temperature at which the reaction is performed will increase the concentration of C2H4, the product of the reaction.

Explanation:

The given reaction is an exothermic reaction as it requires the addition of extra energy of about 52.4KJ in the form of heat for the reaction to proceed towards product formation.

According to L' Chtler principle, when an external constraint is applied to A given system in equilibrium, equilibrium position will shift so as to annul the effect ofnthe constraint imposed on the system.

Therefore, the answers tonthe questions above are given below as follows :

A. The equilibrium will shift towards the right, towards the formation of products in order to remove the effect of the additional heat since the forward reaction is endothermic.

B. The concentration of hydrogen gas will decrease as more of it is used in the formation of products .

C. Increasing the temperature at which the reaction is performed will increase the concentration of C2H4, the product of the reaction as the equilibrium will shift towards the right; formation of products.

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how many moles of sodium are needed to react with sulfuric acid to produce 3.75 moles of sodium sulfate according to the followi
anastassius [24]
Hello!
<span>
You'll need to react 7,5 moles of Sodium with sulfuric acid to produce 3.75 moles of sodium sulfate
</span>
First of all, you need to balance the reaction. The balanced reaction is shown below (ensuring that the Law of Conservation of Mass is met on both sides):

2Na + H₂SO₄ → Na₂SO₄ + H₂

Now, all that you have to do is to use molar equivalences in this reaction applying the coefficients to calculate the moles of Sodium that you'll need:

molesNa=3,75moles Na_{2} SO_4* \frac{2 moles Na}{1 mol Na_{2} SO_4} =7,5 moles Na 

Have a nice day!
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