We could do it with algebra. But we can also do it the long way, which is
shorter than the algebraic way.
The digit in the tens place is 3 times the digit in the units place.
So the number MUST be
31, or
62, or
93 .
It can't be anything else.
Now here they are again, with the reverse of each one:
31 . . . 13 The new number is 18 less.
62 . . . 26 The new number is 36 less.
93 . . . 39 The new number is 54 less.
Obviously, the original number is 62.
-6a+10=-4a-16
-6a+26=-4a
26=2a
A=13
Answer:
I cant see your post...
Step-by-step explanation:
For this case we have the following sequence:
0.8
3.2
12.8
51.2
This sequence can be written as:
0.8 = 0.2 * 4 = 0.2 * 4 ^ 1
3.2 = 0.2 * 16 = 0.2 * 4 ^ 2
12.8 = 0.2 * 64 = 0.2 * 4 ^ 3
51.2 = 0.2 * 256 = 0.2 * 4 ^ 4
Therefore, we have that the generic expression for this case is:
an = 0.2 * 4 ^ n
Then, the next number is then:
a5 = 0.2 * 4 ^ 5 = 0.2 * 1024 = 204.8
answer
the next number in the pattern is 204.8
Answer:
1) 7/3
2) Undefined
3) 1
4) 7/4
Step-by-step explanation:
