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Bezzdna [24]
3 years ago
11

work out three numbers that are in both sequences and between 20 and 40 write the numbers on a single line

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

The nth term of a sequence is 2n + 1

The nth term of a different sequence is 3n  1

Work out the three numbers that are

in both sequences

and

between 20 and 40

Now the three numbers I managed to get are 25, 31 and 37 (as I assumed it meant the output of both of these sequences needs to be the same as well as being in between 20 and 40). For example 2x18+1= 37 as does 3x12+1= 37

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Please Help Me With This Problem
Marysya12 [62]

Answer: i'm sure its c please give me brainlest!

8 0
2 years ago
Brainliest and points !! ANSWER ASAP !!
Igoryamba

Answer:

Step-by-step explanation:

The sum of the ages of a Mother and her son is 78 , three years ago the mother is five times as old as the son, what is their present ages?

To solve this , let the age of the mother be x and the age of the son be y , from the first statement :

x + y = 78

Three years ago , the mother will be x- 3 and the son will be y - 3 , from the second statement:

x - 3 = 5 ( y-3)

x- 3 = 5y - 15

x - 5y = -12

The resulting equations are

x + y = 78

x - 5y = -12

This is called a simultaneous linear equation , that means it is a linear equation.

The side of a square is xcm , if the difference between the area and the perimeter is 12 , find the legth of its side.

Interpretation:

The formula for the area of a square is l^{2} and the perimeter is 4l , from the question , we have

x^{2} - 4x = 12

This is not a linear equation , it is simply a quadratic equation , so the situation is non linear

5 0
3 years ago
Solve 5y^2+20=80, where y is the real number
soldi70 [24.7K]

Answer:

2√3

Step-by-step explanation:

5y2+20=80

Step 1: Subtract 20 from both sides.

5y^2+20−20=80−20

5y^2=60

Step 2: Divide both sides by 5.

5y^2 /5 = 60/5

y2=12

Step 3: Take square root.

y=√12

y=2√3

3 0
3 years ago
Consider these functions:
valkas [14]
I think the answer might be B
6 0
2 years ago
20 business cards are placed in a hat, 10 belong to women, 10 belong yo men If 2 cards are drawn at once. what's the probability
erik [133]

Answer:

First choice:

               \large\boxed{\large\boxed{5/19}}

Explanation:

<em>The probability that the first is a man's card and the second, a woman's card</em> is calculated as the product of both probabilities, taking into account the fact that the second time the number of cards  in the hat has changed.

In spite of it is said that the cards are drawn at once, since it is stated a specific order for the cards (first is a man's card and the second, a woman's card) you can model the procedure as if the cards were drawn consecutively, instead of at once.

<u>1. Probability that the first is a man's card</u>

  • Number of cards in the hat = 20 (the 20 business card)

  • Number of man's card in the hat: 10

  • Probability = favorable oucomes / possible outcomes = 10/20 = 1/2.

<u />

<u>2. Probability that the second is a woman's card</u>

  • Number of cards in the hat = 19 (there is one less card in the hat)

  • Number of wonan's card in the hat: 10

  • Probability = favorable oucomes / possible outcomes = 10/19.

<u>3. Probability that the first is a man's card and the second, a woman's card</u>

<u />

  • (1/2) × (10/19) = 5/19

That is the first choice.

5 0
3 years ago
Read 2 more answers
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