Complete question :
Kaitlin has been given a list of 5 bands and asked to place a vote. Her vote must have the names of her favorite and second favorite bands from the list. How many different votes are possible?
Answer:
20 different votes
Step-by-step explanation:
Total number of bands = 5
To select her favorite ; she chooses 1 from the five ;
Number of bands left = 4
From. The 4 she chooses one ; which is her second favorite
Number of different votes possible :
Favorite selection * second favorite selection
(5 * 4) = 20 different votes.
35=x
180-75=105
X+2x=3x
105=3x
X=35
We try to represent the data in segments from 0 to 20.
<span>The length of the line segment along the number line from 0 to 5 is 5 - 0 = 5 units. The length of the line segment along the number line from 20 to 5 is 20 - 5 = 15 units. If you were to randomly throw a dart on this number line, then the probability of landing in the shaded region is 15/20 = 3/4 or 75%</span>
Answer:
0.888...
Step-by-step explanation:
It depends on how many decimal places you want, or write it as a repeating decimal like I did above. Rounded answers like below would also be correct if you were asked to round it to the nearest tenth, hundredth, thousandth, etc...
0.9
0.89
0.889
0.8889
.
.
.
Answer:
.
Step-by-step explanation:
How many unique combinations are possible in total?
This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination
.
How many out of that 2,118,760 combinations will satisfy the request?
Number of ways to choose 2 red candies out a batch of 28:
.
Number of ways to choose 3 green candies out of a batch of 8:
.
However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing
.
The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:
.
