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Zarrin [17]
3 years ago
9

10 Points

Physics
2 answers:
zaharov [31]3 years ago
8 0
D.radiative zone but I’m not really sure, I’m sorry if it’s wrong
Vinvika [58]3 years ago
4 0
D not positive though
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A parallel-plate air capacitor with a capacitance of 260 pF has a charge of magnitude 0.155 μC on each plate. The plates have a
butalik [34]

Answer:

The potential difference between the plates is 596.2 volts.

Explanation:

Given that,

Capacitance C=260\ pF

Charge q=0.155\ \mu\ C

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We need to calculate the potential difference between the plates

Using formula of potential difference

V= \dfrac{Q}{C}

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V=\dfrac{0.155\times10^{-6}}{260\times10^{-12}}

V=596.2\ volts

Hence,The potential difference between the plates is 596.2 volts.

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3 years ago
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Answer:

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