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Zarrin [17]
3 years ago
9

10 Points

Physics
2 answers:
zaharov [31]3 years ago
8 0
D.radiative zone but I’m not really sure, I’m sorry if it’s wrong
Vinvika [58]3 years ago
4 0
D not positive though
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A wagon is accelerating down a hill. Which statement is true?
Ira Lisetskai [31]
Potential energy decreases and kinetic energy increases.

Potential energy is related to the height, since the wagon is going downhill, height decreases and potential energy decreases.

Kinetic energy is related to the speed, since the wagon is speeding up, kinetic energy increases.
3 0
3 years ago
Why doesn't the skateboarder roll as high each time she goes up the ramp
Westkost [7]

Answer:

The skater has mechanical/gravitational potential energy at the two meter mark. The skater gets to two meters high on the other end of the ramp. In terms of the conservation of energy, the skater will never go higher than two meter on the other end of the the ramp because energy can be neither created nor destroyed.

Explanation:

I hoping it is right!!!∪∧∪     ∪ω∪

6 0
3 years ago
Read 2 more answers
When heat flows from one substance to another, what happens to the temperature of the substance giving off the heat and to the t
blagie [28]
The temperature of the substance giving off the heat decreases while the temperature of the substance receilving the heat increases. they leach what is called equlibrium point where heat energy can longer be exchanged hence equql temperature. this isThermal physics
8 0
3 years ago
An amusement park ride consists of a rotating circular platform 11.1 m in diameter from which 10 kg seats are suspended at the e
frozen [14]

To solve this problem we will use the relationship given between the centripetal Force and the Force caused by the weight, with respect to the horizontal and vertical components of the total tension given.

The tension in the vertical plane will be equivalent to the centripetal force therefore

Tsin\theta= \frac{mv^2}{r}

Here,

m = mass

v = Velocity

r = Radius

The tension in the horizontal plane will be subject to the action of the weight, therefore

Tcos\theta = mg

Matching both expressions with respect to the tension we will have to

T = \frac{\frac{mv^2}{r}}{sin\theta}

T = \frac{mg}{cos\theta}

Then we have that,

\frac{\frac{mv^2}{r}}{sin\theta} =  \frac{mg}{cos\theta}

\frac{mv^2}{r} = mg tan\theta

Rearranging to find the velocity we have that

v = \sqrt{grTan\theta}

The value of the angle is 14.5°, the acceleration  (g) is 9.8m/s^2 and the radius is

r = \frac{\text{diameter of rotational circular platform}}{2} + \text{length of chains}

r = \frac{11.1}{2}+2.41

r = 7.96m

Replacing we have that

v = \sqrt{(9.8)(7.96)tan(14.5\°)}

v = 4.492m/s

Therefore the speed of each seat is 4.492m/s

6 0
3 years ago
The image messed up but you get the point. Don't be mean and just answer to get the points, please and thank you.
Katarina [22]

Answer:

Answer is A, it will pass through to focal point after reflecting.

Explanation:

I had the same question in a test, Sorry that you had to do this question in middle school.

4 0
3 years ago
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