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Zarrin [17]
3 years ago
9

10 Points

Physics
2 answers:
zaharov [31]3 years ago
8 0
D.radiative zone but I’m not really sure, I’m sorry if it’s wrong
Vinvika [58]3 years ago
4 0
D not positive though
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A man stands at the edge of a cliff and throws a rock downward with A speed of 12.0 m s . Sometimes later it strikes the ground
kvasek [131]

B) 48.0 m/s

We can actually start to solve the problem from B for simplicity.

The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation

v^2 -u^2 = 2as

where

v is the final velocity

u = 12.0 is the initial velocity (positive since we take downward as positive direction)

a=g=9.8 m/s^2 is the acceleration of gravity

s = 110 m is the vertical displacement

Solving for v, we find the final velocity (and so, the speed of the rock at impact):

v = \sqrt{u^2+2as}=\sqrt{12^2+2(9.8)(110)}=48.0 m/s

A) 3.67 s

Now we can find the time of flight of the rock by using the following suvat equation

v=u+at

where

v = 48.0 is the final velocity at the moment of impact

u = 12.0 is the initial velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time it takes for the rock to reach the ground

And solving for t, we find

t=\frac{v-u}{a}=\frac{48.0-12.0}{9.8}=3.67 s

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