What is the kinetic energy of a 8kg cat running 5m/s?

Oksana_A [137]

Are you referring to try to get into a college? if you are here is a basic outlay...

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4 0

3 years ago

2. Sally put her mug of coffee on the table. The mug has a mass of 1 kg. if the pressure

egoroff_w [7]

We have,

The mass of sally's mug is 1 kg
The pressure appliedby the mug is 1100 pascal.

We know that,

Pressure = Force/Area

As, we already have the value of pressure, let's calculate that of force now;

F = ma
F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
F = 10 N

Just put all the values in the formula now;

P = F/A
1100 = 10 / A
1100/10 = A
110 m² = A

As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

Surface area = Circumference

So, let's solve it;

Circumference = 2πr
110 = 2 × 22/7 × r
110 × 7/2 × 22 = r
5 × 7 = r
35 cm = r

Thus, the radius of the circle is 35 cm.

7 0

3 years ago

As potential and kinetic energy increase what happens to mechanical energy?

Tom [10]

Answer:

a

Explanation:

7 0

3 years ago

Read 2 more answers

A solvent passes through a chromatography column in 3.0 minutes, but the solute requires 9.0 minutes.

Sergio [31]

Answer:

(a). 2

(b). 1/3

(c). 11.11

Explanation:

(a). k= (t₍s₎-t₍o₎)/t₍o₎...............(1)

where k= retention factor,

t₍o₎=solvent time, t₍s₎= solute time.

Given t₍s₎=9.0 Minutes, t₍o₎=3.0 minutes.

∴ k= (9-3)/3

k= 2.

(b). the fraction of time the solute spend in the mobile phase in the column is the ratio of the solvent time to the solute time. = t₍o₎/t₍s₎..........(2)

= 3/9

=1/3.

(c). K=k(Vm/Vs)................(3)

where K= partition coefficient, k= retention factor, Vm=volume of mobile phase, Vs= volume of stationary phase.

∴K = k(Vm/Vs)

k=2, and Vs=0.18Vm.

∴K = 2(Vm/0.18vm)

⇒K = 2/0.18

∴K=11.11

4 0

3 years ago

A 330 kg piano slides 3.6 m down a 28o incline and is kept from accelerating by a man who is pushing back on it parallel to the

e-lub [12.9K]

Answer:

a. 652.68N

b. -2349.65J

c. -3116.12J

d. 5465.77J

e. Zero

Explanation:

a. According to equilibrium of forces, the force of gravity is equal to the sum of the frictional force and force exerted by the man in the opposite direction (since they're both resistant forces).

Fg = Fm + Fr

Fm = Fg - Fr

Fm = mgsin(28°) - umgcos(28°)

u = coefficient of frictional force.

Fm = 330*9.8*sin28 - 0.4*330*9.8*cos28

Fm = 1518.27 - 865.59

Fm = 652.68N

b. Work done by man is:

Wm = -Fm * d

Wm = -652.68 * 3.6

Wm = -2349.65J

c. Work done by friction force:

W(Fr) = -Fr * d

W(Fr) = -865.59 * 3.6

W(Fr) = -3116.12J

d. Work done by gravity:

Wg = Fg * d

Wg = 1518.27 * 3. 6

Wg = 5465.77J

e. Net work done on the piano is:

Work done by friction + work done by gravity + work done by man

= -3116.12 + 5464.77 + (-2349.65)

= 0J

7 0

3 years ago