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Marysya12 [62]
4 years ago
5

What is the kinetic energy of a 8kg cat running 5m/s?

Physics
1 answer:
ivanzaharov [21]4 years ago
6 0
<span>K.E = 0.5 * m * v^2 ( m = mass(Kg), V = Velocity(m/s)
= 0.5 * 8 * 5^2
= 4 * 25
= 100 J </span>
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Sort the questions based on whether they are better answered by an observational study or a controlled experiment.
Zepler [3.9K]

Answer:

Following questions are better answered by observational study:

- How does the daytime temperature affect the formation of dew at night?

- How effective is a new toothpaste in reducing cavities?

Following questions are better answered by controlled experiment:

- Which is a better absorber of heat, an object painted black or the same object painted white?

- Why does a rolling ball slow down as it moves?

- Can plants prepare food even in artificial light?

Explanation:

An observational study is one in which the researcher doesn't manipulate anything.

In a controlled experiment, the researcher manipulate the outcome of the experiment and controls the factors that might affect the experiment to see different results in different conditions.

So, for questions over which research do not have any control, mostly natural processes, observational study is a better option.

However, to check why a rolling ball slow down, controlled experiments are done to find out all the factors.

Plants placed in artificial light is also an controlled experiment as the researcher will himself place the plants in artificial light and keep them away from natural light.

Similarly, to check if color of the object affects the amount of heat absorbed by that object, a controlled experiment must be performed. Same object should be painted white and observed and then painted black and observed.

7 0
3 years ago
What is the value of the composite constant (Gme,/r2e) to be multiplied by the mass of the object mo, in equation below:
Sedbober [7]

To solve this problem we will apply the definitions given in Newtonian theory about the Force of gravity, and the Force caused by weight. Both will be defined below, and in equal equilibrium condition to clear the variable concerning acceleration due to gravity. Finally, with the values provided in the statement, it will be replaced.

The equation for the gravitational force between the Earth and the object on the surface of the Earth is

F_g = \frac{Gm_em_o}{r^2_e}

Where,

G = Universal gravitational constant

m_e = Mass of Earth

r_e= Distance between object and center of earth

m_o= Mass of Object

The equation for the gravitational pulling force on the object due to gravitational acceleration is

F_g = m_o g

Equation the two expression we have

m_o g = \frac{Gm_em_o}{r_e^2}

g = \frac{Gm_e}{r_e^2}

This the acceleration due to gravity which is composite constant.

Replacing with our values we have then

g = \frac{(6.67*10^{-11}N\cdot m^2/kg^2)(5.98*10^{24}kg)}{6378km(\frac{10^3m}{1km})^2}

g = 9.8m/s^2

The value of composite constant is 9.8m/s^2. Here, the composite constant is nothing but the acceleration due to gravity which is constant always.

8 0
4 years ago
What is peer review?...
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<span>computing or networking is a distributed application architecture that partitions tasks or work loads between peers. Peers are equally privileged, equipotent participants in the application. They are said to form a peer-to-peer network of nodes.</span>
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I think your answer is b
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