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givi [52]
3 years ago
11

I really don’t know what it is to me they r all the same

Physics
2 answers:
Inessa05 [86]3 years ago
4 0
The moon lacks an atmosphere compared to the Earth. Hope this helps!
aleksandr82 [10.1K]3 years ago
3 0
The Moon IS solid, it HAS gravity, and it gets loads of sunlight,
just like the Earth.

But the Earth has air all around it, miles deep. 
The Moon has NO air.  (Choice-C) 
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What animal did wolfgang kohler use to study insight learning
Katena32 [7]

Answer:

He used a chimp to study

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3 years ago
A lorry of mass 4000 kg is travelling at a speed of 4 m/s.
bulgar [2K]

Answer:

KE = 32,000J

v = 8m/s

Explanation:

KE = .5*m*v²

KE = .5*4000kg*(4m/s)²

KE = 32,000J

32,000J = .5*1000kg*v²

v² = 64

v = 8m/s

7 0
3 years ago
If a vibrating string is made shorter (i.e., by holding your finger on it), what effect does
Ghella [55]
  <span>Pitch and frequency are more or less the same thing - high pitch = high frequency. 
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4 0
3 years ago
A bird is flying north with a mass of 2.5kg has a momentum of 17.5kg m/s at what velocity is it flying
klasskru [66]
Momentum = mass • velocity
v= 17.5/2.5
= 7 m/s
8 0
3 years ago
Read 2 more answers
A charged particle moves in a circular path in a uniform magnetic field.Which of the following would increase the period of the
Bond [772]

Answer:

Increasing its charge

Increasing the field strength

Explanation:

For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

qvB = m\frac{v^2}{r}

where

q is the charge

v is the velocity

B is the magnetic field

m is the mass

r is the radius of the orbit

The period of the motion is

T=\frac{2\pi r}{v}

Re-arranging for r

r=\frac{Tv}{2\pi}

And substituting into the previous equation

qvB = m \frac{Tv^3}{2\pi}

Solving for T,

T=\frac{2\pi q B}{m v^2}

So we see that the period is:

- proportional to the charge and the magnetic field

- inversely proportional to the mass and the square of the speed

So the following will increase the period of the particle's motion:

Increasing its charge

Increasing the field strength

4 0
3 years ago
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