The tens digit of a two-digit number is five more than the units digit. Seven times the sum of the digits of this number is 3 le ss than the number itself. Find the number.
2 answers:
Answer:
The correct answer is 94
Step-by-step explanation:
Answer:
43
Step-by-step explanation:
Let
The unit digit = x
The tens digit = y
The number = 10x + y
The tens digit of a two-digit number is five more than the units digit.
y = x + 5
Seven times the sum of the digits of this number is 3 less than the number itself.
7(x + y) = 10x + y - 3
7x + 7y = 10x + y - 3
Find the number.
We substitute x + 5 for y
7x + 7(x + 5) = 10x + (x + 5) - 3
7x + 7x + 35 = 10x + x + 5x - 3
14x + 35 = 11x + 5x - 3
Collect like terms
35 + 3 = 11x + 5x -14x
38 = 16x - 14x
38 = 2x
x = 38/2
x = 19
Solving for y
y = x + 5
y = 19 + 5
y = 24
The number = 19 + 24
= 43
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Answer:
B
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Step-by-step explanation:
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Answer:
d.
Step-by-step explanation:
The red graph is the black one times 2.
So y = 2 f(x). which is the same as y/2 = f(x) (divide by 2).
C = 22d is the correct answer because for every day the cost increases by 22 so two days mean the cost is equal to 22 (2)
Yes is the answer click it
