Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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(2x-3)<5 now add3yo all dlide
-2<2x<8then devide by 2
-1<x<4then x belongs to(-1,4)
Answer:
Graph B
Step-by-step explanation:
the "x" and "y" represent 
so therefore, it's
,
,
, 
you would start at (0,0) or the origin
and count over one and up one, or however many units the fraction/chart tells you to count up
64x² - 36 factors to be (8x + 6)(8x - 6)
Option C is your answer.
HOWEVER, I cannot tell what the operation is supposed to be performed because of the way it is showing up above (see attached pic). So I can also just simplify it.
64x² - 36 becomes 4(16x² - 9) or 4(4x - 3)(4x + 3)
64x² + 36 becomes 4(16x² + 9)
It is close to 8. When you look for the square root of 59 you should get about 7.6811457... Round up and thats 8 round down that 7 but it should be 8.