Answer:
correct substrate to bind the active site of the enzyme.
Explanation:
For an enzyme to catalyze a chemical reaction it is very essential for the correct substrate to bind the active site of the enzyme.
The Active site consists of two parts
1.Binding site
2. Catalytic site
The binding site consists of amino acid residues that bind to the correct substrate while the catalytic site has the amino acids that lead to the catalysis.
The active site's shape is such that only the right substratum easily binds to it and thus the catalytic reaction occurs.
132 grams x (1 mol / 44 grams) = 3 moles
<span>3 moles X (22.4 L/ 1 mol) = 67.2 </span><span>L</span>
SOLUTION :
Law of conservation of Mass States that "Mass is neither created, nor destroyed".
→ Like Mass of Reactants = Mass of products.
REACTANTS :
- Mass of Sodium Carbonate(given) = 5.3g
- Mass of ethanoic acid(given)= 6g
The total mass of reactants:
= 5.3 + 6
= 11.3g
<h3>•Products are :</h3>
- Mass of Carbon Dioxide = 2.2g
- Mass of Sodium ethanoate = 8.2g
The total mass of products is :
= 2.2 + 0.9 + 8.2
= 3.1 + 8.2
= 11.3g
Hence the, Mass of Reactants = Mass of products
∴ The given reaction is in agreement with the law of conservation.
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Answer:-
Solution:- The equation for the conversion of gold ions to gold metal is as follows:
From this equation, 1 mol of Gold metal is deposited by 3 mole of electrons.
We know that one mol of electron carries one Faraday that is 96500 Coulombs.
So. 3 moles of electrons would be = 3(96500) = 289500 Coulombs
We could calculate the total Coulombs by using the formula:
q = i*t
where, q is the charge in coulombs, i is the current in ampere and t is time in seconds.
q =
q = 51408 ampere per second
Since, 1 ampere per second = 1 coulomb
So, 51408 ampere per second is same as 51408 coulombs.
Let's use this value of q and the info from balanced equation and molar mass(196.967 g epr mol) of gold to calculate the mass of it being deposited while the current is passed as:
= 35.0 g Au
So, 35.0 g of gold are deposited on passing 23.8 ampere of current for 36.0 min to a gold solution.
Answer: 127 m
Explanation:
4500 mg/L . 35.5 g/mol = 127 m