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ra1l [238]
3 years ago
12

A closed container in lab contains a sample of oxygen gas. When the temperature in lab is 16.3 degrees Celcius, the pressure in

the container is 9.30 atm. What would the temperature in lab be (in Celcius) if the pressure in the container was 17.7 atm? Assume the mol and volume of the container are constant. Record your answer as a number with the correct significant figures.
Chemistry
2 answers:
koban [17]3 years ago
5 0

Answer:

????????

Explanation:

ololo11 [35]3 years ago
4 0

Answer:

T₂  = 550.60 K

Explanation:

Given data:

Initial temperature = 16.3°C (16.3+273 = 289.3 K)

Initial pressure = 9.30 atm

Final temperature = ?

Final pressure = 17.7 atm

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

9.30 atm / 289.3 K = 17.7 atm/T₂

T₂ =  17.7 atm × 289.3  K / 9.30 atm

T₂  = 5120.61 atm. K /9.30 atm

T₂  = 550.60 K

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How many liters of ammonia (NH3), at 3.2 atm and 23C, must be used to produce of 2.65 grams of calcium hydride (CaH2). 6 Ca(s)
7nadin3 [17]

Answer:

The answer to your question is    V = 0.32 L

Explanation:

Data

Volume of NH₃ = ?

P = 3.2 atm

T = 23°C

mass of CaH₂ = 2.65 g

Balanced chemical reaction

               6Ca  +  2NH₃   ⇒   3CaH₂  +  Ca₃N₂

Process

1.- Convert the mass of CaH₂ to moles

-Calculate the molar mass of CaH₂

 CaH₂ = 40 + 2 = 42 g

                             42 g ------------------ 1 mol

                              2.65 g --------------  x

                              x = (2.65 x 1)/42

                              x = 0.063 moles

2.- Calculate the moles of NH₃

                     2 moles of NH₃ --------------- 3 moles of CaH₂

                      x                        --------------- 0.063 moles

                                x = (0.063 x 2) / 3

                                x = 0.042 moles of NH₃

3.- Convert the °C to °K

Temperature = 23°C + 273

                      = 296°K

4.- Calculate the volume of NH₃

-Use the ideal gas law

              PV = nRT

-Solve for V

                V = nRT / P

-Substitution

                V = (0.042)(0.082)(296) / 3.2

-Simplification

               V = 1.019 / 3.2

-Result

               V = 0.32 L

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Woof. Hope it helps!!! :) ....Reason*

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Answer: A

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