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Pachacha [2.7K]
3 years ago
8

Construct a three-step synthesis of 1,2-epoxycyclopentane from cyclopentanol by dragging the appropriate formulas into the bins.

Note that each bin will hold only one item, and not all of the given reagents or structures will be used.

Chemistry
1 answer:
zubka84 [21]3 years ago
3 0

Answer:

(1) Bromination, (2) E2 elimination and (3) epoxidation

Explanation:

  • In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with PBr_{3}
  • In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
  • In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
  • Full reaction scheme has been shown below

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<u>Explanation:</u>

It is given that the volume of the gas divided by the temperature is 1.75.

V/T = 1.75

As per the Charles law, volume is proportional to the temperature.

V ∝ T

V/T = constant

Now we have to find V, and T is given as 300 K.

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Elements and compounds are more similar to each other than they are to mixtures because:
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Answer:

elements and compounds can only be liquids or solids, but mixtures can be solids, liquids or gases

Explanation:

Element: A substance that is made up of only one type of atom. Compound: A substance that is made up of more than one type of atom bonded together. Mixture: A combination of two or more elements or compounds which have not reacted to bond together; each part in the mixture retains its own properties.

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Explanation:

1

Number of nucleon =

Molarmassofnucleon

Massofatom

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2

You have 4.70 mol H2O

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Therefore, there must be 2*4.70 = 9.40 mols H in 4.70 mols H2O.

How many mols O in 4.70 mols H2O? That's 4.70 mols, of course.

Said another way, you have 2 mols H for every 1 mol H2O and 1 mol O for every 1 mol H2O.

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Harlamova29_29 [7]

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

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