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2 years ago

Body temperature is controlled by a negative feedback control system. the hypothalamus is the ________ for this system.

Chemistry

1 answer:

postnew [5]2 years ago

6 0

Body temperature is controlled by a negative feedback control system.

What is negative feedback?

In biological systems, a type of control known as negative feedback occurs when a process's output lowers its own stimulus. A common regulation mechanism in many biological responses is feedback. The body may regulate numerous aspects of its internal environment by permitting particular routes to be switched on and off. This is like turning a switch. Feedback enables a pathway's output to operate a switch. Negative feedback, often known as a "negative feedback loop," happens when a pathway's end product disables the corresponding metabolic step.

In order to maintain body temperature, the hypothalamus reacts to this information by directing nerve impulses to effectors. For instance, the hair erector muscles tighten up if we get too cold. As a result, a layer of air is trapped near to the skin, raising the skin hairs. Systematic negative feedback regulates body temperature.

Thus the hypothalamus is the vital organ for this system.

To learn more about negative feedback from the given link below,

brainly.com/question/11525272

#SPJ4

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3 years ago

A student dissolves 10.7 g of lithium chloride (LiCl) in 300. g of water in a well-insulated open cup. He then observes the temp

Novosadov [1.4K]

Answer:

1) Exothermic.

2) $Q_{rxn}=-8580J$

3) $\Delta _rH=-121.0kJ/mol$

Explanation:

Hello there!

1) In this case, for these calorimetry problems, we can realize that since the temperature increases the reaction is exothermic because it is releasing heat to solution, that is why the temperature goes from 22.0 °C to 28.6 °C.

2) Now, for the total heat released by the reaction, we first need to assume that all of it is absorbed by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

$Q_{rxn}=-m_{Total}C(T_2-T_1)\\\\Q_{rxn}=-(300g+10.7g)*4.184 \frac{J}{g\°C} (28.6\°C-22.0\°C)\\\\Q_{rxn}=-8580J$

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case LiCl, we proceed as follows:

$\Delta _rH=\frac{Q_{rxn}}{n_{LiCl}} \\\\\Delta _rH=\frac{-8580J}{10.7g*\frac{1mol}{150.91g} }*\frac{1kJ}{1000J} \\\\\Delta _rH=-121.0kJ/mol$

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