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3 years ago

Irrational numbers are imaginary. true or false

Mathematics

2 answers:

maxonik [38]3 years ago

7 0

Answer: true true true

Vedmedyk [2.9K]3 years ago

3 0

Imaginary numbers are not rational which may lead you to believe that they must be irrational. Though logical, you would still be incorrect because “irrational” also applies only to real numbers.

Step-by-step explanation:

You might be interested in

What is a repeating decimal give an example

Svetach [21]

<h3>to explain it briefly... a decimal number with a digit ( or group of digits ) that repeats forever</h3>

some examples would be - - -

1/3 = 0.333... ( the 3 repeats forever )
1/3 = 0.333... ( the 3 repeats forever )

hope that helps :)

7 0

3 years ago

Show that (3m+4n)2 –48mn= (3m-4n)2

damaskus [11]

Answer:

9m2+16n2+24mn-48mn

9m2+16n2-24mn

(3m-4n)2

6 0

3 years ago

Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to

bonufazy [111]

Answer:

-48

Step-by-step explanation:

Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words

$\int\limits_C {L(x,y)} \, dx + M(x,y) \, dy = \int\limits_0^2\int\limits_0^2 (M_x - L_y ) \, dx \, dy$

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,

M(x,y) = 4x²y
Mx(x,y) = 8xy
L(x,y) = 10y²x
Ly(x,y) = 20xy
Mx - Ly = -12xy

Therefore, the line integral can be computed as follows

$\int\limits_C {10y^2x} \, dx + {4x^2y} \,dy = \int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy$

Using the linearity of the integral and Barrow's Theorem we have

$\int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy = -12 \int\limits_0^2\int\limits_0^2 xy \, dx \, dy = -12 \int\limits_0^2\frac{x^2y}{2} |_{x = 0}^{x=2} \, dy = -12 \int\limits_0^22y \, dy \\= -24 ( \frac{y^2}{2} |_0^2) = -24*2 = -48$

As a result, the value of the double integral is -48-

3 0

4 years ago

A 10 ft pole has a support rope that extends from the top of the pole to the ground. The rope and the ground form a 30 degree an

mr Goodwill [35]

Answer:

The length of rope is 20.0 ft . Hence, <u>option (1) </u> is correct.

Step-by-step explanation:

In the figure below AB represents pole having height 10 ft and AC represents the rope that is from the top of pole to the ground. BC represent the ground distance from base of tower to the rope.

The rope and the ground form a 30 degree angle that is the angle between BC and AC is 30°.

In right angled triangle ABC with right angle at B.

Since we have to find the length of rope that is the value of side AC.

Using trigonometric ratios

$\sin C=\frac{\text{perpendicular}}{\text{hypotenuse}}$