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gladu [14]
3 years ago
9

Find the value of:x^0+3​

Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

4

Step-by-step explanation:

x^0 means 1. so 1+3=4

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Add all of the interior angles to 1260. Then you simplify for x. After that you plug in what you found for X in the E expression. 

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3 years ago
FINANCE
VMariaS [17]

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Step-by-step explanation:

4 0
2 years ago
Solving Exponential Equations (lacking a common base)<br> 31^d=38
Bond [772]

Answer:

d = log 38/log31

d = 1.06

Step-by-step explanation:

31 ^ d = 38

Take log of both sides since the exponential equation have different base (always)

d log 31 = log 38

d = log 38 / log 31

d = 1.58 / 1.491

d = 1.06.

We can actually check to see if this is correct.

Substituting d = 1.06

31^ 1.06 = 38.092

(You see, that's approximately correct)

Keep learning, maths is fun!

8 0
3 years ago
Joe has one book each for algebra, geometry, history, psychology, Spanish, English and Physics in his locker. How many different
Alisiya [41]

Answer:

There are 35 different sets of 3 books Joe could choose

Step-by-step explanation:

* Lets explain how to solve the problem

- Combination is a collection of the objects where the order doesn't

 matter

- The formula for the number of possible combinations of r objects from

 a set of n objects is nCr = n!/r!(n-r)!

- n! = n(n - 1)(n - 2)................. × 1

Lets solve the problem

- Joe has one book each for algebra, geometry, history, psychology,

 Spanish, English and Physics in his locker

∴ He has <em>seven</em> books in the locker

- He wants to chose <em>three</em> of them

∵ The order is not important when he chose the books

∴ We will use the combination <em>nCr</em> to find how many different sets

  of three books he can choose

- The total number of books is 7

∴ n = 7

∵ He chooses 3 of them

∴ r = 3

∵ 7C3 = 7!/3!(7 - 3)! = 7!/3!(4!)

∴ 7C3=\frac{(7)(6)(5)(4)(3)(2)(1)}{[(3)(2)(1)][(4)(3)(2)(1)]}=35

∴ 7C3 = 35

* There are 35 different sets of 3 books Joe could choose

3 0
3 years ago
A 2 cm x 2 cm x 2 cm cube holds 468 grains of rice. How many grains of rice would fit in a box with
Amiraneli [1.4K]
Let the Volume of the first cube be V1

V1 = 2 * 2 * 2

= 8 cm*3


Let the Volume of the second cube be V2

V2 = 6 * 2 * 12

= 144 cm*3


Now, cube1 with volume of 8 cm*3 holds 468 grains of rice.

Thus, 1 cm*3 volume can hold 58.5 grains of rice ( 468 / 8 = 58.5)

Cube2 has volume of 144 cm*3.

Hence, it can hold 8424 grains of rice ( 144 * 58.5 = 8424)
4 0
3 years ago
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