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Marina86 [1]
2 years ago
7

Kate is 17 years old and victor is 12 years younger. In how many years will kate be twice as old as victor

Mathematics
2 answers:
vazorg [7]2 years ago
8 0

Answer:

In 2 years

Step-by-step explanation:

When Kate turns 20, Victor will be 10.

20 is twice as much as 10 (10*2=20)

hope this helps!

frozen [14]2 years ago
6 0

Answer:

In 7 years Kate will be twice as old as Victor

Step-by-step explanation:

Victors age: 17-12=5

Kate's age:17+7=24

Victors age:5+7=12

24 divided by 2 equals to 12.

~~~~~~~

Check your answer

5+12=17

24-7=17

12-7=5

12*2=24

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A delivery truck drives three routes in one day. The first route is 1223 miles long, the second route is 1034 miles long, and th
avanturin [10]

Answer:

Total = 38\frac{11}{12}\ miles

Step-by-step explanation:

Given

First\ Route = 12\frac{2}{3}\ miles

Second\ Route = 10\frac{3}{4}\ miles

Third\ Route = 15\frac{1}{2}\ miles

Required

Determine the total miles

Total = First\ Route + Second\ Route + Third\ Route

Total = 12\frac{2}{3} + 10\frac{3}{4} + 15\frac{1}{2}

Convert to improper fractions

Total = \frac{38}{3} + \frac{43}{4} + \frac{31}{2}

Take LCM

Total = \frac{152 + 129 + 186}{12}

Total = \frac{467}{12}

Total = 38\frac{11}{12}\ miles

5 0
3 years ago
If 2^21 = x + 2^20, what is the value of x ?
andrew-mc [135]

Answer:

x = 1048576

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
In circle O, what is m∠MAJ? °
mr_godi [17]

See the attached figure.

m ∠KAJ = 170° &  m ∠LAM = 80°

We should know that :

m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°

∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)

∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°

But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>

∴ m ∠MAJ + m ∠MAJ = 110°

∴ 2 * m ∠MAJ = 110°

∴ m ∠MAJ = 110° ÷ 2 = 55°


<u>So, the answer is :  m ∠MAJ = 55°</u>

4 0
3 years ago
What property says that -12+12+0
natali 33 [55]

Answer:

Looks like <u>inverse property of addition </u>to me

4 0
3 years ago
The can of tomatoes is three times as tall but one-third as wide as the can of tuna. What is true about the areas of their label
yulyashka [42]
Problem One
Call the radius of the second can = r
Call the height of the second can = h

Then the radius of the first can = 1/3 r
The height of the first can = 3*h

A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h] 

Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel

Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.

Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.

If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder. 

One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h

Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h

Answer: Upper left corner  <<<<< Answer
8 0
3 years ago
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