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2 years ago

Kate is 17 years old and victor is 12 years younger. In how many years will kate be twice as old as victor

Mathematics

2 answers:

vazorg [7]2 years ago

8 0

Answer:

In 2 years

Step-by-step explanation:

When Kate turns 20, Victor will be 10.

20 is twice as much as 10 (10*2=20)

hope this helps!

frozen [14]2 years ago

6 0

Answer:

In 7 years Kate will be twice as old as Victor

Step-by-step explanation:

Victors age: 17-12=5

Kate's age:17+7=24

Victors age:5+7=12

24 divided by 2 equals to 12.

~~~~~~~

Check your answer

5+12=17

24-7=17

12-7=5

12*2=24

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A delivery truck drives three routes in one day. The first route is 1223 miles long, the second route is 1034 miles long, and th

avanturin [10]

Answer:

$Total = 38\frac{11}{12}\ miles$

Step-by-step explanation:

Given

$First\ Route = 12\frac{2}{3}\ miles$

$Second\ Route = 10\frac{3}{4}\ miles$

$Third\ Route = 15\frac{1}{2}\ miles$

Required

Determine the total miles

$Total = First\ Route + Second\ Route + Third\ Route$

$Total = 12\frac{2}{3} + 10\frac{3}{4} + 15\frac{1}{2}$

Convert to improper fractions

$Total = \frac{38}{3} + \frac{43}{4} + \frac{31}{2}$

Take LCM

$Total = \frac{152 + 129 + 186}{12}$

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3 years ago

If 2^21 = x + 2^20, what is the value of x ?

andrew-mc [135]

Answer:

x = 1048576

Step-by-step explanation:

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3 years ago

Read 2 more answers

In circle O, what is m∠MAJ? °

mr_godi [17]

See the attached figure.

m ∠KAJ = 170° & m ∠LAM = 80°

We should know that :

m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°

∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)

∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°

But : m ∠KAL = m ∠MAJ ⇒⇒⇒ Opposite angles.

∴ m ∠MAJ + m ∠MAJ = 110°

∴ 2 * m ∠MAJ = 110°

∴ m ∠MAJ = 110° ÷ 2 = 55°

So, the answer is : m ∠MAJ = 55°

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3 years ago

What property says that -12+12+0

natali 33 [55]

Answer:

Looks like inverse property of addition to me

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3 years ago

The can of tomatoes is three times as tall but one-third as wide as the can of tuna. What is true about the areas of their label

yulyashka [42]

Problem One
Call the radius of the second can = r
Call the height of the second can = h

Then the radius of the first can = 1/3 r
The height of the first can = 3*h

A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]

Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel

Result A1 / A2 = 1/1
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Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.

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Put the 2 regions together and you get
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3 years ago