The answer to the question is y=-24x
Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
ur answer
and thank u for following me
1/4
since there is 4 letters in the word math
so 1 out of 4
<em>Hope it helps...</em>
<span><span><span>3x</span>+<span>4y</span></span>=8
</span>Add -4y to both sides
<span><span><span><span>3x</span>+<span>4y</span></span>+<span>−<span>4y</span></span></span>=<span>8+<span>−<span>4y</span></span></span></span><span><span>3x</span>=<span><span>−<span>4y</span></span>+8
</span></span>Then you divide both sides by 3
<span><span><span>3x/</span>3</span>=<span><span><span>−<span>4y</span></span>+8/</span>3</span></span><span>x=<span><span><span><span>−4/</span>3</span>y</span>+<span>8/3
</span></span></span>And your answer is ...
<span>x=<span><span><span><span>−4/</span>3</span>y</span>+<span>8/<span>3</span></span></span></span>
