Answer:

Explanation:
When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:

Where:
vf = final velocity
vo = initial velocity
a = acceleration
x = distance
Solving for a:

The car travels a distance of x=200 m and the velocities are:
vo = 216 Km/h
vf = 360 Km/h
Both velocities must be converted to meters by seconds.
vo = 216 Km/h *1000/3600 = 60 m/s
vf = 360 Km/h *1000/3600 = 100 m/s
The acceleration is:




I think that it might be B?
Tell me if im wrong
Answer:
7327 kg or 7.3 tons
Explanation:
We have Newton formula for attraction force between 2 objects with mass and a distance between them:

where
is the gravitational constant on Earth.
is the masses of the 2 objects. and R = 2.6m is the distance between them.
is the attraction force.



or 7.3 tons
Mechanical energy E = mgh + 1/2mv²
When he starts, let h = 0 ⇒ E₁ = 1/2mv₁²
When he reaches height h ⇒ E₂ = mgh + 1/2mv₂²
Without friction, energy is conserved at all times.
E₁ = E₂
↓
1/2mv₁² = mgh + 1/2mv₂²
↓
1/2v₁² = gh + 1/2v₂²
↓
gh = 1/2(v₁² - v₂²)
↓
h = (v₁² - v₂²) / (2g)
Answer:
The answer is C she didn't mark C so its your best best of trying.Good Luck!