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Ksju [112]
3 years ago
5

The force that keeps two surfaces at rest from sliding over each other is

Physics
1 answer:
natka813 [3]3 years ago
8 0
Friction is the correct answer.
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A car travelled a distance of 200 m with initial velocity of 216 km/hr. Calculate the acceleration
pogonyaev

Answer:

a = 16\ m/s^2

Explanation:

When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:

v_f^2=v_o^2+2ax

Where:

vf = final velocity

vo = initial velocity

a = acceleration

x = distance

Solving for a:

\displaystyle a=\frac{v_f^2-v_o^2}{2x}

The car travels a distance of x=200 m and the velocities are:

vo = 216 Km/h

vf = 360 Km/h

Both velocities must be converted to meters by seconds.

vo = 216 Km/h *1000/3600 = 60 m/s

vf = 360 Km/h *1000/3600 = 100 m/s

The acceleration is:

\displaystyle a=\frac{100^2-60^2}{2*200}

\displaystyle a=\frac{10000-3600}{400}

\displaystyle a=\frac{6400}{400}

\mathbf{a = 16\ m/s^2}

7 0
3 years ago
A chicken flaps off the roof of the henhouse with a velocity of 4.5 m/s north. The chicken lands 2.8 seconds later. If a hungry
katrin2010 [14]
I think that it might be B?
                                  Tell me if im wrong
8 0
3 years ago
Two trucks with equal mass are attracted to each other with a gravitational force of 5.3 x 10 -4 N. The trucks are separated by
HACTEHA [7]

Answer:

7327 kg or 7.3 tons

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408*10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M = M_1 = M_2 is the masses of the 2 objects. and R = 2.6m is the distance between them.

F_G = 5.3*10^{-4}N is the attraction force.

5.3*10^{-4} = 6.67408*10^{-11}\frac{M^2}{2.6^2}

7941265 = \frac{M^2}{2.6^2}

M^2 = 53682948.76

M = \sqrt{53682948.76} \approx 7327 kg or 7.3 tons

3 0
4 years ago
A skateboarder is moving 5.25 m/s when he starts to roll up a frictionless hill. How much higher is he when his velocity has red
Taya2010 [7]
Mechanical energy E = mgh + 1/2mv²

When he starts, let h = 0 ⇒ E₁ = 1/2mv₁²
When he reaches height h ⇒ E₂ = mgh + 1/2mv₂²

Without friction, energy is conserved at all times.

E₁ = E₂
     ↓
1/2mv₁² = mgh + 1/2mv₂²
     ↓
1/2v₁² = gh + 1/2v₂²
     ↓
gh = 1/2(v₁² - v₂²)
    ↓
h = (v₁² - v₂²) / (2g)


5 0
4 years ago
Read 2 more answers
Please tell the correct answer​
alukav5142 [94]

Answer:

The answer is C she didn't mark C so its your best best of trying.Good Luck!

8 0
3 years ago
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