It will act upon a buoyant force on the magnitude of which is equal to weight of the fluid
There is no acceleration of g in the x direction because the gravitational acceleration points downward. Also, on most studies we ignore the tidal forces since we are dealing with small bodies compared to the size of the earth.
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The answer to your question is dioxygen carbide
Answer:
The maximum value of the induced magnetic field is
.
Explanation:
Given that,
Radius of plate = 30 mm
Separation = 5.0 mm
Frequency = 60 Hz
Suppose the maximum potential difference is 100 V and r= 130 mm.
We need to calculate the angular frequency
Using formula of angular frequency
![\omega=2\pi f](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%20f)
Put the value into the formula
![\omega=2\times\pi\times60](https://tex.z-dn.net/?f=%5Comega%3D2%5Ctimes%5Cpi%5Ctimes60)
![\omega=376.9\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D376.9%5C%20rad%2Fs)
When r>R, the magnetic field is inversely proportional to the r.
We need to calculate the maximum value of the induced magnetic field that occurs at r = R
Using formula of magnetic filed
![B_{max}=\dfrac{\mu_{0}\epsilon_{0}R^2\timesV_{max}\times\omega}{2rd}](https://tex.z-dn.net/?f=B_%7Bmax%7D%3D%5Cdfrac%7B%5Cmu_%7B0%7D%5Cepsilon_%7B0%7DR%5E2%5CtimesV_%7Bmax%7D%5Ctimes%5Comega%7D%7B2rd%7D)
Where, R = radius of plate
d = plate separation
V = voltage
Put the value into the formula
![B_{max}=\dfrac{4\pi\times10^{-7}\times8.85\times10^{-12}\times(30\times10^{-3})^2\times100\times376.9}{2\times130\times10^{-3}\times5.0\times10^{-3}}](https://tex.z-dn.net/?f=B_%7Bmax%7D%3D%5Cdfrac%7B4%5Cpi%5Ctimes10%5E%7B-7%7D%5Ctimes8.85%5Ctimes10%5E%7B-12%7D%5Ctimes%2830%5Ctimes10%5E%7B-3%7D%29%5E2%5Ctimes100%5Ctimes376.9%7D%7B2%5Ctimes130%5Ctimes10%5E%7B-3%7D%5Ctimes5.0%5Ctimes10%5E%7B-3%7D%7D)
![B_{max}=2.901\times10^{-13}\ T](https://tex.z-dn.net/?f=B_%7Bmax%7D%3D2.901%5Ctimes10%5E%7B-13%7D%5C%20T)
Hence, The maximum value of the induced magnetic field is
.
The car should have a velocity of 60 m/s to attain the same momentum as that of the truck of 2000 kg.
Answer:
Explanation:
Momentum is measured as the product of mass of object with the velocity attained by that object.
Momentum of 2000 kg truck = Mass × Velocity
Momentum of 2000 kg truck = 2000×30 = 60000 N
Similarly, the momentum of 1000 kg car will be 1000× velocity of the 1000 kg car.
Since, it is stated that momentum of 2000 kg truck is equal to the momentum of 1000 kg of car, then the velocity of 1000 kg of car can be determined by equating the momentum of car and truck.
Momentum of 2000 kg truck = Momentum of 1000 kg car
60000=1000×velocity of 1000 kg car
Velocity of 1000 kg car = 60000/1000=60 m/s
So, the car should have a velocity of 60 m/s to attain the same momentum as that of the truck of 2000 kg.