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jonny [76]
3 years ago
11

Choose the sources of gamma rays. Check all that apply.

Physics
1 answer:
harina [27]3 years ago
7 0

Answer:

a. Stars all warm objects

c. Some unstable atomic nuclei

Explanation:

Gamma rays are photons of very high energy (beyond 100keV) enough to remove an electron from its orbit.

They have a very short wavelength, less than 5 meters from the peak, and can be produced by nuclear decay, especially in the breasts of massive stars at the end of life.

They were discovered by the French chemist Paul Villard (1860 to 1934).

While X-rays are produced by electronic transitions in general caused by the collision of an electron with an atom at high speed, gamma rays are produced by nuclear transitions.

 Gamma rays produce damage similar to those caused by X-rays or ultraviolet rays (burns, cancer and genetic mutations).

The sources of gamma rays that we observe in the universe come from <u>massive stars (hypernovas) or some warm objects on the space</u> that end their lives by a gravitational collapse that leads to the formation of a neutron star or a black hole, as well as <u>unstable radioactive nuclei </u>that emit radiation gamma to reach its steady state.

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An ideal parallel-plate capacitor consists of a set of two parallel plates of area Separated by a very small distance 푑. This ca
dolphi86 [110]

Answer:

doubled the initial value

Explanation:

Let the area of plates be A and the separation between them is d.

Let V be the potential difference of the battery.

The energy stored in the capacitor is given by

U = Q^2/2C   ...(1)

Now the battery is disconnected, it means the charge is constant.

the separation between the plates is doubled.

The capacitance of the parallel plate capacitor is inversely proportional to the distance between the plates.

C' = C/2

the new energy stored

U' = Q^2 /  2C'

U' = Q^2/C = 2 U

The energy stored in the capacitor is doubled the initial amount.

8 0
3 years ago
A driver in a car traveling at a speed of 50 mi/h sees a deer 50 m away on the road. Calculate the minimum constant acceleration
alisha [4.7K]

Answer:

a= - 0.79 m/s²

Explanation:

Given that

Speed ,u = 20 mi/h

We know that

1 mi/h= 0.44 m/s

Therefore ,u = 8.94 m/s

Distance ,s= 50 m

Lets take the acceleration of the car = a m/s²

The final speed of the car ,v = 0 m/s

We know that

v²= u² + 2 a s

Now by putting the values

0²= 8.94² + 2 x a x 50

a=-\dfrac{8.94^2}{2\times 50}\ m/s^2

a= - 0.79 m/s²

Therefore the acceleration will be - 0.79 m/s².

6 0
3 years ago
A concave mirror with a radius of curvature of 20 cm has a focal length of
xxTIMURxx [149]

Answer:

A concave mirror has a radius of curvature of 20 cm. What is it's focal length? If an object is placed 15 cm in front of it, where would the image be formed? What is it's magnification?

The focal length is of 10 cm, object distance is 30 cm and magnification is -2.

Explanation:

Given:

A concave mirror:

Radius of curvature of the mirror, as C = 20 cm

Object distance in-front of the mirror = 15 cm

a.

Focal length:

Focal length is half of the radius of curvature.

Focal length of the mirror =  \frac{C}{2} = 10 cm

According to the sign convention we will put the mirror on (0,0) point, of the Cartesian coordinate open towards the negative x-axis.

Object and the focal length are also on the negative x-axis where focal length and image distance will be negative numerically.

b.

We have to find the object distance:

Formula to be use:

⇒ \frac{1}{focal\ length}= \frac{1}{image\ distance} + \frac{1}{object\ distance}

⇒ Plugging the values.

⇒ \frac{1}{-10} =\frac{1}{image\ distance}+\frac{1}{-15}

⇒ \frac{1}{-10} -\frac{1}{-15}=\frac{1}{image\ distance}

⇒ \frac{1}{-10} + \frac{1}{15}=\frac{1}{image\ distance}

⇒ \frac{-3+2}{30} =\frac{1}{image\ distance}

⇒ \frac{-1}{30} =\frac{1}{image\ distance}

⇒ -30\ cm=image\ distance

Image will be formed towards negative x-axis 30 cm away from the pole.

c.

Magnification (m) is the negative ratio of mage distance and object distance:

⇒ m=-\frac{image\ distance}{object\ distance}

⇒ m=-\frac{(-30)}{(-15)}

⇒ m=-2

The focal length of the concave mirror, is of 10 cm, object distance is 30 cm and magnification is -2.

5 0
3 years ago
The strength of force is expressed by a. Weight b.mass
HACTEHA [7]

Answer:

Weight.

Explanation:

4 0
3 years ago
What is vertical displacement
nataly862011 [7]
Distance in the y direction.
5 0
3 years ago
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