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Airida [17]
3 years ago
6

Can someone explain this problem 71.8 ÷ ¾

Mathematics
1 answer:
avanturin [10]3 years ago
4 0

Answer:

95.733333

Step-by-step explanation:

IDK if this is right

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Lostsunrise [7]
The minimum number of points in a line is equal to to two. When there are three points already, these can still make a line, anyway. Therefore, it does not necessarily mean that when three points are present, they should form only a plane not a line. Answer thus is false. 
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4 years ago
Solve by applying the counting principle. James is choosing a Four-digit Passcode for his smartphone. How many different Passcod
EleoNora [17]

Answer:

10k.

Step-by-step explanation:

1) if for the 1st position can be used 0-9 digits (10 digits), for the 2d - 0-9 digits, for the 3d - 0-9 digits and for the 4th - 0-9 digits, then

2) the required number of pwd is: 10*10*10*10=10⁴=10000.

4 0
2 years ago
2x+y=3<br>x-y= 1<br><br>solve the equation ​
svetlana [45]

Answer:

x = 4/3

y = 1/3

Step-by-step explanation:

System of equations! This is set up really well to make the second equation equal x then substitute.

x - y = 1

x = 1 + y

and then our substitution:

2 (1+y) + y = 3

and solve:

2 + 2y + y = 3

3y + 2 = 3

3y = 1

y = 1/3

And now we can substitute that value into one of our equations:

x - (1/3) = 1

x = 4/3

Next we should check by substituting these values into both of our equations:

2 (4/3) + (1/3) = 3

9 / 3 does equal 3 !

(4/3) - (1/3) does equal 1 !

Therefore, x = 4/3 , and y = 1/3

4 0
3 years ago
Read 2 more answers
Tell me at least one way you use math in your everyday life. Please put your answer in a complete sentence.
iris [78.8K]

Answer:

To make mistakes and learn more.

Step-by-step explanation:

Because, the only way to learn math is to make mistakes, its okay to make mistakes!

8 0
3 years ago
Read 2 more answers
What is the solution set of the equation using the quadratic formula?
oee [108]

(1)

we are given

x^2+6x+10=0

we can use quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a , b and c

we get

a=1,b=6,c=10

now, we can plug these values into quadratic formula

x=\frac{-6\pm \sqrt{6^2-4(1)(10)}}{2(1)}

x=\frac{-6+\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}

we can simplify it

x=-3+i

x=\frac{-6-\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}

x=-3-i

so, we will get solution

{−3+i, −3−i}.........Answer

(2)

we are given equation as

x^2-8x+14=0

Since, Jamal solve this equation by completing square

so, firstly we will move constant term on right side

so,  subtract both sides by 14

x^2-8x+14-14=0-14

x^2-8x=-14

we can write

-8x=-2\times 4\times x

so, we will add both sides by 4^2

x^2-8x+4^2=-14+4^2

we get

x^2-8x+16=-14+16..............Answer


4 0
3 years ago
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