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Alex777 [14]
3 years ago
9

Suppose real GDP is forecasted to grow by 2.78 %, the velocity of money has been stable, and the Fed announces an inflation targ

et of 3.70 %. What is the largest money growth rate the Fed could implement and still achieve its inflation target
Business
1 answer:
Vadim26 [7]3 years ago
6 0

Answer: 6.48%

Explanation:

This can be solved using the Quantity theory of money;

MV = PY

When dealing with changes, formula changes to;

% change in Money Supply + %change in velocity = %change in price + %change in real GDP

Velocity has been stable so will be zero.

change in money supply = 3.70% + 2.78%

= 6.48%

You might be interested in
Gray is a 50% partner in Fabco Partnership. Gray's tax basis in Fabco on January 1, year 4, was $5,000. Fabco made no distributi
arsen [322]

Answer:

$21000

Explanation:

To determine Gray’s tax basis  for a 50% interest in the Fabco Partnership, The interest is increased by the partner’s  distributive share of all partnership items of income and decreased by the partner’s distributive share of all loss and  deduction items.

Gray’s beginning basis = $5,000  

Gray’s 50% distributive share of ordinary  income = 50% × $20000 = $10000

Gray’s 50% tax-exempt income= 50% × $8000 = $4,000 and  

portfolio income = 50% × $4000  = $2,000

Therefore, the ending basis of  Gray’s Fabco partnership interest = $5000 + $10000 + $4000 + $2000 = $21000

6 0
3 years ago
Bob makes his first $ 800 deposit into an IRA earning 7.4 % compounded annually on his 24th birthday and his last $ 800 deposit
Likurg_2 [28]

Answer:The answer is $17,387.67

Explanation:

Let Principal = P, Rate = R% per annum, Time = n years

Amount = P ( 1 + R/100)∧n

P = $800, R = 7.4%, n = 24

A = 800 ( 1 + 7.4/100)∧24

A = 800 ( 1 + 0.074)∧24

A = 800 ( 1 .074)∧24

A = 800 (5.547569512)

A = 800× 5.5475569512

A = $4,438.05

Deposit made at 39th birthday

P = $800, R = 7.4%, n = 39

A = 800 ( 1 + 7.4/100)∧39

A = 800 (1 + 0.074)∧39

A = 800 (1.074)∧39

A = 800 (16.187022604)

A = 800× 16.187022604

A = $12,949.62

How much is in the IRA when Bob retires will be

$4,438.05 + 12,949.62

= $17,387.67

6 0
3 years ago
Benchmarking involves:
creativ13 [48]

Answer:

1. comparing how different companies perform various value chain activities and then making cross-company comparisons of the costs and effectiveness of these activities.

Explanation:

Benchmarking -

It is the method of comparing the business performance and the process like the cost , time and quality .

Benchmarking is also known as process benchmarking , or , best practice benchmarking .

It is the comparison among various companies , that how the company performs various value chain activities .

Hence , from the question , the correct statement for the given term is ( 1. ) .

5 0
3 years ago
The table below shows the average income of the U.S. total population over age 25, based on level of education. Drag the differe
abruzzese [7]

The differences in average income are $6,080, $6169, $18,219, and $19,151.

The table below organizes income from the one with the lowest education level to the highest one. Moreover, there is a general trend in which income increases with education.

Now, to find the difference in average income based on education it is necessary to subtract the income of a lower level to the income of the next educational level.

Less than Highschool vs. High school graduate:

  • $31,956 - $25,876 = $6,080

High school graduate vs. some college or Associate's degree:

  • $38,125 - 31,956 = $6169

Some college or Associate's degree vs. Bachelor's degree:

  • $56,344 - $38,125 = $18,219

Bachelor's degree vs Profession or Doctorate degree:

  • $75,495 - $56,344 = $19,151

Learn more about mathematics in: brainly.com/question/12083755

4 0
2 years ago
​Joe's starting salary as a mechanical engineer is around ​$100 comma 000. Joe is planning to place a total of 13​% of his salar
Maru [420]

Answer:

$ 2,209,797.96

Explanation:

Given:

Salary = $100,000

Salary investment rate = 13%

Salary increase rate(g) = 5%

number of year = 25

Annual rate of return(i) = 11%

Calculation:

Salary invested = $100,000*13% = $13,000

calculation of present worth

P=A[\frac{1-(1+g)^n(1+i)^{-n}}{i-g}] \\P=13000[\frac{1-(1+0.05)^{25}(1+0.11)^{-25}}{0.11-0.05}] \\P=13000[\frac{1-(1.05)^{25}(1.11)^{-25}}{0.06}] \\P=13000[\frac{1-(3.386354)(0.073608086)}{0.06}]\\\\P=13000[\frac{1-0.249263}{0.06}]\\\\ P=13000[12.5122827]\\\\\\P= 162,659.675

Future worth = P(1+i)^n\\                       = 162,659.675(1+0.11)^{25}\\                       = 2,209,797.96

3 0
3 years ago
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