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Yuliya22 [10]
3 years ago
6

Mr. D'Agostino decided he wanted to build a pool in his backyard this summer. He sketched a drawing that had a scale of 1 in. =

4 feet. If the drawing had a length of 4 feet and a width of 5 feet, what is the actual area of the pool?
Mathematics
1 answer:
Travka [436]3 years ago
5 0

Answer:

46080 ft²

Step-by-step explanation:

Given :

Scale :

1 in = 4 feets

Recall :

I foot =. 12 inches

Length of drawing = 4 feets

Length of drawing in inches = 4 * 12 = 48 inches

Width of drawing = 5 feets

Width of drawing in inches = 5 * 12 = 60 inches

Actual length of pool = 48 * 4 = 192 feets

Actual width of pool = 60 * 4 = 240 feets

The actual area of the pool :

Length * width

192 feets * 240 feets = 46080 ft²

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