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3 years ago

A number with 2 or more factors.

Mathematics

2 answers:

Molodets [167]3 years ago

7 0

Answer:

composite number. that is what it is called

Step-by-step explanation:

mario62 [17]3 years ago

5 0

Answer:

a composite number 15 i think because its one and itself

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Without a calculator how would you solve this?

mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

$\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6$

$=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}$

$\bigstar\ (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}$

$\bigstar\ \bigstar\ (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}$

$\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702$

$\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6$

$0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0$

$\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0$

$\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702$

8 0

3 years ago

Solve for x 35+.8x=43-7x

Vinvika [58]

Answer:

x = 1.02564

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

35 + 0.8x = 43 - 7x

Step 2: Solve for x

[Addition Property of Equality] Add 7x on both sides: 35 + 7.8x = 43
[Subtraction Property of Equality] Subtract 35 on both sides: 7.8x = 8
[Division Property of Equality] Divide 7.8 on both sides: x = 1.02564

7 0

3 years ago

HELP! WILL MARK BRAINLIEST IF CORRECT!

mariarad [96]

I think it’s 25???? i tried haha

8 0

3 years ago

Use the Rational Zero Theorem to list all possible rational zeros for the given function. f(x) = 10x^5 + 8x^4 - 15x^3 +2x^2 - 2

vagabundo [1.1K]

Given:

The function is:

$f(x)=10x^5+8x^4-15x^3+2x^2-2$

To find:

All the possible rational zeros for the given function by using the Rational Zero Theorem.

Solution:

According to the rational root theorem, all the rational roots are of the form $\dfrac{p}{q},q\neq 0$ , where p is a factor of constant term and q is a factor of leading coefficient.

We have,

$f(x)=10x^5+8x^4-15x^3+2x^2-2$

Here,

Constant term = -2

Leading coefficient = 10

Factors of -2 are ±1, ±2.

Factors of 10 are ±1, ±2, ±5, ±10.

Using the rational root theorem, all the possible rational roots are:

$x=\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}$ .

Therefore, all the possible rational roots of the given function are $\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}$ .

5 0

3 years ago

Given two angles that measure 50 degrees and 80 degrees and a side that measures 4 feet, how many triangles, if any, can be cons

Elza [17]

Since we have the triangle, but don't know which side 4 is on, we have one where x is opposite a 50 degree angle (they are the same if across either 50 degree side) and another across the 80 degree one. In addition, it's really ratios and sin/cos/tan from there!

3 0

3 years ago

Read 2 more answers