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malfutka [58]
3 years ago
9

Please help

Mathematics
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

Option A:

y = 3*(x - 5)^2 - 4

Step-by-step explanation:

For a quadratic equation:

y = a*x^2 + b*x + c

with the vertex (h, k), we can rewrite the function as:

such that:

h = -b/2*a

y = a*(x - h)^2 + k

Here we have the function:

y = 3*x^2 - 30*x + 71

the x-value of the vertex will be:

h = -(-30)/(2*3) = 30/6 = 5

And k is given by:

k = y(5) = 3*(5)^2 - 30*5 + 71 = -4

Then the vertex is:

(5, - 4)

And we can rewrite the equation in the vertex form as:

y = 3*(x - 5)^2 + (-4)

y = 3*(x - 5)^2 - 4

Then the correct option is A.

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We need to prove that the product of two rational numbers is always rational. A rational number is a number that can be stated as the quotient or fraction of two integers : a numerator and a non-zero denominator.

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