The escape velocity of the dwarf planet is 1,721.8 m/s.
The given parameters:
- <em>Mass of the dwarf planet, m = 0.0045 M</em>
- <em>Mass of the Earth = 5.98 x 10²⁴ kg</em>
- <em>Diameter of the planet, d = 0.19 D</em>
- <em>Diameter of the Earth, D = 12,742 km</em>
The mass of the of the dwarf planet is calculated as follows;
The radius of the dwarf planet is calculated as follows;
The escape velocity of the dwarf planet is calculated as follows;
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There are no acceptable descriptions at all on that list of choices.
Answer:
1.4s
Explanation:
Given parameters:
Mass of ball = 2kg
Force = 8N
Time = 0.35s
Unknown:
Change in velocity = ?
Solution:
To solve this problem, we use the expression obtained from Newton's second law of motion which is shown below:
Ft = m(v - u)
So;
Ft = m Δv
F is the force
t is the time
m is the mass
Δv is the change in velocity
8 x 0.35 = 2 x Δv
Δv = 1.4s
Answer:
A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc.
