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QveST [7]
3 years ago
5

If something is traveling at a constant velocity are forces balanced or unbalanced?

Physics
2 answers:
lubasha [3.4K]3 years ago
7 0

Answer:

If something is traveling at a constant velocity, then forces are balanced.

Explanation:

If something is traveling at a constant velocity, then the forces must be balanced because a constant velocity is only achieved with balanced forces.

<em>Please </em><em>like </em><em>and </em><em>mark </em><em>brainliest</em><em>!</em><em> </em>

<em>Hope </em><em>it </em><em>helps!</em>

alex41 [277]3 years ago
3 0
The forces is balanced at a constant velocity it would be unbalanced if it was speeding up or slowing down
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Answer:

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Explanation:

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Which of the following affects the rate constant of a reaction?
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A the entropy of the reaction I think ion know if that’s correct
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2 years ago
An electric motor can drive grinding wheel at two different speeds. When set to high the angular speed is 2000 rpm. The wheel tu
shutvik [7]

a) The initial angular speed is 209.3 m/s

b) The angular acceleration is -1.74 rad/s^2

c) The angular speed after 40 s is 139.7 rad/s

d) The wheel makes 1501 revolutions

Explanation:

a)

The initial angular speed of the wheel is

\omega_i = 2000 rpm

which means 2000 revolutions per minute.

We have to convert it into rad/s. Keeping in mind that:

1 rev = 2\pi rad

1 min = 60 s

We find:

\omega_i = 2000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=209.3 rad/s

b)

To find the angular acceleration, we have to convert the final angular speed also from rev/min to rad/s.

Using the same procedure used in part a),

\omega_f = 1000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=104.7 rad/s

Now we can find the angular acceleration, given by

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_i = 209.3 rad/s is the initial angular speed

\omega_f = 104.7 rad/s is the final angular speed

t = 60 s is the time interval

Substituting,

\alpha = \frac{104.7-209.3}{60}=-1.74  rad/s^2

c)

To find the angular speed 40 seconds after the initial moment, we use the equivalent of the suvat equations for circular motion:

\omega' = \omega_i + \alpha t

where we have

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 40 s, we find

\omega' = 209.3 + (-1.74)(40)=139.7 rad/s

d)

The angular displacement of the wheel in a certain time interval t is given by

\theta=\omega_i t + \frac{1}{2}\alpha t^2

where

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 60 s, we find:

\theta=(209.3)(60) + \frac{1}{2}(-1.74)(60)^2=9426 rad

So, the wheel turns 9426 radians in the 60 seconds of slowing down. Converting this value into revolutions,

\theta = \frac{9426 rad}{2\pi rad/rev}=1501 rev

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

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8 0
3 years ago
2. What value did you calculate for the index of refraction of the acrylic block in Part 2? How does your value compare to the a
lesya [120]

The percentage error in calculated value of the refractive index of acrylic block is calculated using the formula: (true value - calculated value/true value) × 100%.

<h3>What is refractive index of a refracting medium?</h3>

The refractive index of a medium is the ratio of the sine of the angle of incidence on the medium and the sine of the angle of refraction.

  • Refractive index = sin i/sin r

where;

  • i is the angle of incidence
  • r is angle of refraction.

The refractive index of a medium increases with density of the medium.

To determine the percentage error in determining the refractive index of a medium, the following formula is used:

  • Percent error = error/true value × 100%

Therefore, the percentage error in calculated value of the refractive index of acrylic block is the ratio of the error and true value multiplied by 100%.

Learn more about refractive index at: brainly.com/question/83184

8 0
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A student exerts a force of 500 n pushing a box 10 m across the floor in 4 s. how much work does the student perform?
gregori [183]
Work = Force * distance
W = Fd

Given F = 500 N, d = 10 m
W = (500)(10)
W = 5000 J

The work done is 500 Joules. The time of 4 s is irrelevant in this case.
6 0
3 years ago
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