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3 years ago

If something is traveling at a constant velocity are forces balanced or unbalanced?

Physics

2 answers:

lubasha [3.4K]3 years ago

7 0

Answer:

If something is traveling at a constant velocity, then forces are balanced.

Explanation:

If something is traveling at a constant velocity, then the forces must be balanced because a constant velocity is only achieved with balanced forces.

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Hope it helps!

alex41 [277]3 years ago

3 0

The forces is balanced at a constant velocity it would be unbalanced if it was speeding up or slowing down

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Magnetic induction cannot be done in a wood why

NikAS [45]

Answer:

Magnetic induction cannot be done in a wood because it is not a magnetic person like iron , nickel,and cobalt

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3 years ago

Two children of mass 18 kg and 29 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the c

DedPeter [7]

Answer:

3.085 [m].

Explanation:

1) The rule:

m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;

2) according to the condigion l₁+l₂=5, then

3) it is possible to make up the system:

$\left \{ {{l_1+l_2=5} \atop {m_1*l_1=m_2*l_2}} \right. \ = > \ \left \{ {{l_1=5-l_2} \atop {18*(5-l_2)=29*l_2}} \right. \ = > \ \left \{ {{l_1=\frac{145}{47}} \atop {l_2=\frac{90}{47}}} \right.$

4) finally, l₁=145/47≈3.085 [m].

7 0

2 years ago

Car A is traveling at 20.0 m/s and car B at 27.0 m/s.

Savatey [412]

Take the moment car A starts to accelerate to be the origin. Then car A has position at time t

x = (20.0 m/s) t + 1/2 (2.10 m/s²) t²

and car B's position is given by

x = 300 m + (27.0 m/s) t

Car A overtakes car B at the moment their positions are equal:

(20.0 m/s) t + 1/2 (2.10 m/s²) t² = 300 m + (27.0 m/s) t

300 m + (7.00 m/s) t - (1.05 m/s²) t² = 0

==> t ≈ 20.6 s

4 0

3 years ago

The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.

Reika [66]

Answer:

$tan \theta = \mu_s$

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

$mg sin \theta - \mu_s R =0$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, $\theta$ the angle of the slope

$\mu_s R$ is the frictional force, with $\mu_s$ being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

$R-mg cos \theta = 0$

where

R is the normal reaction

$mg cos \theta$ is the component of the weight perpendicular to the slope

Solving for R,

$R=mg cos \theta$

And substituting into (1)

$mg sin \theta - \mu_s mg cos \theta = 0$

Re-arranging the equation,

$sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s$

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of $\mu_s$ , the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0

4 years ago

There is a basketball with a diameter of 9in. and a softball with a diameter of 4in. Find how many times greater the volume of t

erica [24]

Answer: #.37 times greater

Explanation: Volume of a sphere is: V = $\frac{4}{3}$ ·π·r³

Since it is given the diameter of the basketball and the softball, their ratios are r₁ = 3in and r₂ = 2in, in which index 1 represents the basketball and index 2, the softball.

Calculating the volume of basketball:

V₁ = $\frac{4}{3}$ . 3.14 . 3³

V₁ = 113.04 in³

Calculating the volume of softball:

V₂ = $\frac{4}{3}$ . 3.14 . 2³

V₂ = 33.5 in³

Comparing one volume with the other:

$\frac{V1}{V2}$ = $\frac{113.04}{33.5}$ = 3.37