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likoan [24]
2 years ago
5

Help, please!!!!! I just need help putting the vocab word in the box where it belongs.

Physics
1 answer:
Ber [7]2 years ago
8 0

here's the first part but for the 2nd one all I know is that the word "compression" goes on the spirals that are closer together.

hope this helps!

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Photons of wavelength 65.0 pm are Compton-scattered from a free electron which picks up a kinetic energy of 0.75 keV from the co
DIA [1.3K]

0.6764*10^-10m

Explanation:

Using E= hc/wavelength

(4.14x10^-15)x(3.0x10^8)/(65x10^-12)=0.1911x10^5 eV=19.1 keV

So subtract the calculated energy from the given energy of scattered photons

9.11-0.75=18.36 keV

To find wavelength

Wavelength= hc/ E

[(4.14x 10^-15)x (3.0x10^8)]/(18.36*10^3) =0.6764^-10 m

8 0
3 years ago
Entific findings are useful
Kaylis [27]

That's true.  The give-away is "observation ... in the real world".  That's what "field reports" are.

The part I'm not so sure about is those "entific findings".

4 0
2 years ago
Explain the relationship between force, mass and acceleration in Newton's second law
Nikitich [7]

Newton's  second law of motion describes what happens to a body when an external  force is applied to it.

Newton's second law of motion states that the force acting on an object is equal to the mass of that object times its acceleration. In mathematical form this is written as

F = ma

Where F is force , m is mass and a is acceleration. The math or logic  behind this is that if  you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.


7 0
3 years ago
A bus is moving and has 500000 joules of kinetic energy. The brakes are applied and the bus stops. How much work is needed to st
Bad White [126]
For the work-energy theorem, the work needed to stop the bus is equal to its variation of kinetic energy:
W=K_f - K_i
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus

Since the bus comes at rest, its final kinetic energy is zero: K_f = 0, so the work done by the brakes to stop the bus is
W=-K_i = -500000 J
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
8 0
2 years ago
"2.40 A pressure of 4 × 106N/m2 is applied to a body of water that initially filled a 4300 cm3 volume. Estimate its volume after
wel

Answer:Final volume after pressure is applied=4,292cm3

Explanation:

Using the bulk modulus formulae

We have that The bulk modulus of waTer is given as  

K =-V dP/dV

Where  K, the bulk modulus of water = 2.15 x 10^9N/m^2

2.15 x 10^9N/m^2= - 4,300 x  4 × 106N/m2 / dV

dV = - 4,300 x  4 × 10^6N/m^2/ 2.15 x 10^9N/m^2

dV (change in volume)= -8.000cm^3

Final volume after pressure is applied,

V= V+ dV

V= 4300cm3 + (-8.000cm3)

=4300cm3 - 8.000cm3

Final Volume, V =4,292cm3

3 0
3 years ago
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