Answer:
The frequency of the oscillation is 0.9Hz
Explanation:
This problem bothers on simple harmonic motion of a spring
Given data
Mass of the child m= 25kg
Spring constant k=791 N/m
Amplitude a= 31cm
But the period of the motion as a result of the adults sholve is expressed as
T=2π√m/k
T=2*3.142√25/791
T=6.284√0.031
T=6.284*0.176
T=1.11 sec
But frequency F=1/T
F=1/1.11
F=0.9Hz
Answer:
20 m
Explanation:
From the equation of motion,
S = ut+1/2gt²................................. Equation 1
Where S = Height, u = initial velocity, t = time, g = acceleration due to gravity.
Note: Because the rocked is being dropped from a height, acceleration due to gravity is positive (g), and initial velocity (u) is negative
Given: t = 2.0 s, g = 10 m/s², u = 0 m/s (dropped from height)
Substituting into equation 1
S = 0(2) + 1/2(10)(2)²
S = 5(4)
S = 20 m
Hence the height of the the cliff above the pool is 20 m
There must be movement in the same direction as the force put on the object. Hope this helps!
Answer:
The value of resistance when power is 1100 watts = 
= 50 ohms
Explanation:
Power 
= 2200 Watts
Resistance 
= 25 ohms
Power 
= 1100 Watts
Resistance = we have to calculate
Given that the power in an electric circuit varies inversely with the resistance
⇒ P ∝ 
⇒ 
= 
⇒ 
= 
⇒ = 50 ohms
This is the value of resistance when power is 1100 watts.
