Answer:
The time needed is 
Explanation:
From the question we are told that
The magnitude of the stimulated acceleration due gravity is 
The diameter of the spaceship is 
Generally the force acting on the spaceship is
Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so
Thus
=> 
Generally the speed of this spaceship is mathematically represented as
=> ![v^2 = [\frac{2\pi}{T}] ^2](https://tex.z-dn.net/?f=v%5E2%20%20%3D%20%20%20%5B%5Cfrac%7B2%5Cpi%7D%7BT%7D%5D%20%5E2)
=> 
=> 
=> 
substituting values
The answer to the question
Wearing rubber or stay away from water or/ and a conductor
Answer:
a = -0.33 m/s² k^
Direction: negative
Explanation:
From Newton's law of motion, we know that;
F = ma
Now, from magnetic fields, we know that;. F = qVB
Thus;
ma = qVB
Where;
m is mass
a is acceleration
q is charge
V is velocity
B is magnetic field
We are given;
m = 1.81 × 10^(−3) kg
q = 1.22 × 10 ^(−8) C
V = (3.00 × 10⁴ m/s) ȷ^.
B = (1.63T) ı^ + (0.980T) ȷ^
Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;
a = qVB/m
a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))
From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^
Thus;
a = -0.33 m/s² k^
