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notsponge [240]
3 years ago
14

Whats the 4th term in 12 - n

Mathematics
1 answer:
never [62]3 years ago
5 0

Answer:

2n

Step-by-step explanation:

To find the 1st term, put n = 1 into the formula, to find the 4th term, replace the n's by 4's: 4th term = 2 × 4 = 8.

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Your school district cancels schools when more than 2.5 inches of snow accumulate on the ground each hour. Snow is currently acc
kari74 [83]

Answer:

Extra snow needed > 0. 3 inch

Step-by-step explanation:

Given that:

Cancelation occurs when > 2.5 inch of snow accumulates each hour

Accumulation rate = 11/5 inch per hour

Extra snow Accumulation needed to cancel. School ;

Extra snow needed > cancelation volume - current rate

Extra snow needed > (2.5 - 11/5)

Extra snow needed > 0. 3 inch

5 0
3 years ago
14c^3d^2-21c^2d^3/14cd
levacccp [35]

14c³d²-21c²d³/14cd

= (196c^4d³-21c²d³)/ 14cd

= (196c³d²-21cd²)/14

= (28c³d²-3cd²)/2


I hope that's help !

3 0
3 years ago
Ahmet is twice as old as his sister Betul, and the sum of their ages is 36. How old is Ahmet?
Dovator [93]
18??
two times as old.
36 divided but 2 is 18
4 0
3 years ago
Three times a number added to six is equal to five times the same number.
NISA [10]
Here you go if you need help solving I’ve got you

7 0
3 years ago
Read 2 more answers
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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