Answer:
I would not like to take your place but I can help you find someone. I don't have a laughing emoji. (On my computer)
Thet contradict each other, that's why both of them are incorrect.
<span>Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form.
p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial
This polynomial has a degree of at least 4. It therefore cannot be cubic.
Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do.
(x - 1)(x - 2)(x - 3)
This is a cubic polynomial with three roots, and four or more roots are not possible for a cubic polynomial. Kelsey is correct.
Incidentally, if this is a roller coaster we are discussing, then a cubic polynomial is not such a good idea, either for a vertical curve or a horizontal curve. I hope this helps</span><span>
</span>
Answer:
44% is the probability
Step-by-step explanation:
Answer:
Step-by-step explanation:
Simplify the equation 
Since
and
we have
Answer:
f(3) = -13
Step-by-step explanation:
f(x)= - x²-4 (not (-x)²)
f(3) = - 3² - 4 = - 9 - 4 = -13
