The current in the circuit drops and reduces, because of the higher voltage.
Because of the higher potential difference, the current in the circuit reduces as well.
Answer:
8.9
Explanation:
We can start by calculating the initial elastic potential energy of the spring. This is given by:
(1)
where
k = 35.0 N/m is the initial spring constant
x = 0.375 m is the compression of the spring
Solving the equation,
![U=\frac{1}{2}(35.0)(0.375)^2=2.5 J](https://tex.z-dn.net/?f=U%3D%5Cfrac%7B1%7D%7B2%7D%2835.0%29%280.375%29%5E2%3D2.5%20J)
Later, the professor told the student that he needs an elastic potential energy of
U' = 22.0 J
to achieve his goal. Assuming that the compression of the spring will remain the same, this means that we can calculate the new spring constant that is needed to achieve this energy, by solving eq.(1) for k:
![k'=\frac{2U'}{x^2}=\frac{2(22.0)}{0.375^2}=313 N/m](https://tex.z-dn.net/?f=k%27%3D%5Cfrac%7B2U%27%7D%7Bx%5E2%7D%3D%5Cfrac%7B2%2822.0%29%7D%7B0.375%5E2%7D%3D313%20N%2Fm)
Therefore, Tom needs to increase the spring constant by a factor:
![\frac{k'}{k}=\frac{313}{35}=8.9](https://tex.z-dn.net/?f=%5Cfrac%7Bk%27%7D%7Bk%7D%3D%5Cfrac%7B313%7D%7B35%7D%3D8.9)
Answer:
Magnetic flux will be equal to
Explanation:
It is given radius of circular loop r = 0.10 m
Area of circular loop ![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
![A=3.14\times 0.10^2=0.0314m^2](https://tex.z-dn.net/?f=A%3D3.14%5Ctimes%20%200.10%5E2%3D0.0314m%5E2)
Magnetic field B = 0.20 T
Angle between plane of loop and magnetic field ![\Theta =30^{\circ}](https://tex.z-dn.net/?f=%5CTheta%20%3D30%5E%7B%5Ccirc%7D)
Magnetic flux will be equal to ![\Phi =BAcos\Theta](https://tex.z-dn.net/?f=%5CPhi%20%3DBAcos%5CTheta)
![\Phi =0.2\times 0.0314\times cos30^{\circ}=5.43\times 10^{-3}weber](https://tex.z-dn.net/?f=%5CPhi%20%3D0.2%5Ctimes%200.0314%5Ctimes%20cos30%5E%7B%5Ccirc%7D%3D5.43%5Ctimes%2010%5E%7B-3%7Dweber)
So magnetic flux will be equal to ![5.43\times 10^{-3}weber](https://tex.z-dn.net/?f=5.43%5Ctimes%2010%5E%7B-3%7Dweber)
Yes, <span> the moon fall partly into earth's shadow when it is in its full size</span>