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Igoryamba
3 years ago
7

Which of the following statements is true of space exploration?

Physics
1 answer:
elena-s [515]3 years ago
6 0
You don't have a following space exploration
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A reaction has a rate constant of 0.0117 s-1 at 400.0 k and 0.689 s-1 at 450.0 k. calculate the activation energy in kilojoules
Zina [86]
By definition we have to:
 LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
 Where,
 k1 = 0.0117 s-1
 K2 = 0.689 s-1
 T1 = 400.0 k
 T2 = 450.0 k
 R is the ideal gas constant
 R = 8.314 KJ / (Kmol * K)
 Substituting
 ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
 Clearing Ea:
 Ea = 122 kJ
 answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
<span>
</span>
7 0
3 years ago
Read 2 more answers
According to the reading, which of the following is NOT an obstacle to using big data for analysis and decision making? O Poor r
RoseWind [281]

Answer:

B .Limited types of data Insufficient data

Explanation:

To analyse and making decision from big data we have following thing

- Sufficient data

- data analyst

- Accurate data

- data Privacy

- data storage

So, limited data or data that cannot be copied is not and obstacle in data handling. hence option B Limited types of data Insufficient data is correct.

3 0
4 years ago
I need an answer to question number 4 ASAP
Nat2105 [25]

Answer:

Screwing

Explanation:

3 0
4 years ago
Bose-Einstein Condensate can be defined by Group of answer choices slowly vibrating molecules all possibilities listed are corre
deff fn [24]

Answer:

The correct option is;

Absolute zero

Explanation:

A Bose-Einstein condensate is known as the fifth state of matter which is made of a collection of ultra cooled atoms (at almost absolute zero degrees -273.15 °C) such that the there is very slight free energy within the atoms which results in almost no relative motion between the atoms. The atoms then combine forming clumps such that phenomena usually observed at the microscopic level such as wavefunction interference become observable at the microscopic level.

4 0
3 years ago
Two physics students are standing on skateboards and facing each other. Their masses, including the skateboards, are 95 kg and 5
andrey2020 [161]

Answer:

1) \sum \vec p=0\ kg.m.s^{-1}

2) v_2=55.078\ m.s^{-1}

Explanation:

Given:

  • mass of heavier student, m_1=95\ kg
  • mass of lighter student, m_2=58\ kg
  • velocity of the heavier student after the mutual push, v_1=3.1\ m.s^{-1}

1)

Since they push each other and we are neglecting any friction that means we can consider this as a perfectly elastic collision. So the momentum of the two bodies will be equal and in opposite direction.

Since momentum is a vector quantity so the total momentum of the system as a whole will be zero.

2)

<u>From the condition of elastic collision:</u>

p_1=p_2

m_1.v_1=m_2.v_2

95\times 3.1=58\times v_2

v_2=55.078\ m.s^{-1}

6 0
4 years ago
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