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FromTheMoon [43]
3 years ago
9

Think of an everyday situation in which two objects interact and exert a force on each other. Explain how the interaction can ca

use energy to be transferred from one object to the other
Chemistry
1 answer:
blondinia [14]3 years ago
6 0

Answer:

It's explained below.

Explanation:

An everyday situation is when we raise an object.

Now, when we raise an object, energy is transferred to the Earth object system and thus the gravitational field energy of the system will increase.

Now, this energy is usually released when the object falls. The mechanism of this release is known as gravitational force.

In the same manner, two magnetic and electrically charged objects that are interacting at a distance will exert forces on each other and this can lead to transfer of energy between the interacting objects.

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Any physical matter that is obtained or made from plants, animals, or the ground without undergoing a chemical process is called
ziro4ka [17]

Any physical matter that is obtained or made from plants, animals, or the ground without undergoing a chemical process is called a natural material. This is a true statement.

<h3>Features of natural materials</h3>

Natural materials are the physical matters that are made from plants, animals and ground(environment) which has not been subjected to any chemical processes for modification.

But any natural material that has undergone any chemical process which has been designed and manufactured to fulfil a particular purpose is called a synthetic material.

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2 years ago
What Can You Tell About The Shape Of The Compound Made Of Magnesium &amp; Nitrogen ?
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3 0
3 years ago
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.74 g of water at 52.2 oC in an insulated container. clead = 0.128
QveST [7]

Answer:

Explanation:

Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):

DH_{lead}=-DH_{water}

Now, by stating the heat capacity definition:

m_{Pb}C_{Pb}*(T_{eq}-T_{lead}=-m_{H_2O}C_{H_2O}*(T_{eq}-T_{H_2O})\\

Solving for the equilibrium temperature:

T_{eq}=\frac{m_{Pb}C_{Pb}T_{Pb}+m_{H_2O}C_{H_2O}T_{H_2O}}{m_{Pb}C_{Pb}+m_{H_2O}C_{H_2O}} \\\\T_{eq}=\frac{2.04g*0.128J/(g^oC)*10.8^oC+7.74g*4.18J/(g^oC)*52.2^oC}{2.04g*0.128J/(g^oC)+7.74g*4.18J/(g^oC)} \\\\T_{eq}=51.87^oC

Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.

Best regards.

5 0
3 years ago
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